(New page: == Original Code == <pre> F0 =13; T0 =1/F0; Ts = 0.07; t = 0:Ts:13*T0; x = real(exp(j*(2*pi*F0*t-pi/2))); </pre> The problem with this code is that since its current frequency is 13 Hz...) |
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From his reference i decided to use a new timestep of Ts/10000. which turns out to be .07/10000 for my deltaT | From his reference i decided to use a new timestep of Ts/10000. which turns out to be .07/10000 for my deltaT | ||
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Revision as of 06:46, 12 September 2008
Original Code
F0 =13; T0 =1/F0; Ts = 0.07; t = 0:Ts:13*T0; x = real(exp(j*(2*pi*F0*t-pi/2)));
The problem with this code is that since its current frequency is 13 Hz, this causes a problem with the timestep of a Discrete Time signal which shows why there is a bug in this code. The timestep in this case makes the part of the signal that is plotted is considered to small to get a full sample.
In order to fix this code I have referenced Aishwar Sabesan to see values of a new timestep to use to save time (I could have figured it out on my own but I would rather have values in the ballpark before I began)
From his reference i decided to use a new timestep of Ts/10000. which turns out to be .07/10000 for my deltaT
