(→Prove) |
(→Prove) |
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Line 17: | Line 17: | ||
[1] | [1] | ||
− | x1(t)--->[system]---->y1(t)=2x1(t)---->*a | + | x1(t)--->[system]---->y1(t)=2x1(t)---->*a---(1) a*2*x1(t) |
− | x2(t)--->[system]---->y2(t)=2x2(t)---->*b | + | x2(t)--->[system]---->y2(t)=2x2(t)---->*b---(2) b*2*x2(t) |
(1)+(2)= 2ax1(t)+2bx2(t) | (1)+(2)= 2ax1(t)+2bx2(t) | ||
Line 27: | Line 27: | ||
[2] | [2] | ||
− | x1(t)--->*a --- (3) a*x1(t) | + | x1(t)--->*a---(3) a*x1(t) |
− | x2(t)--->*b --- (4) b*x2(t) | + | x2(t)--->*b---(4) b*x2(t) |
(3)+(4)=a*x1(t)+b*x2(t) ---->[system]---->2(a*x1(t)+b*x2(t))=2ax1(t)+2bx1(t) | (3)+(4)=a*x1(t)+b*x2(t) ---->[system]---->2(a*x1(t)+b*x2(t))=2ax1(t)+2bx1(t) | ||
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y(t)=x(t)^2 | y(t)=x(t)^2 | ||
− | [ | + | [3] |
− | x1(t)--->[system]---->y1(t)=x1(t)^2---->*a | + | x1(t)--->[system]---->y1(t)=x1(t)^2---->*a---(5)a*x1(t)^2 |
− | x2(t)--->[system]---->y2(t)=x2(t)^2---->*b | + | x2(t)--->[system]---->y2(t)=x2(t)^2---->*b---(6)b*x2(t)^2 |
− | ( | + | (5)+(6)= a*x1(t)^2+b*x2(t)^2 |
− | [ | + | [4] |
− | x1(t)--->*a --- ( | + | x1(t)--->*a---(7)a*x1(t) |
− | x2(t)--->*b --- ( | + | x2(t)--->*b---(8)b*x2(t) |
− | ( | + | (7)+(8)=a*x1(t)+b*x2(t) ---->[system]---->(a*x1(t)+b*x2(t))^2 |
− | The results of [ | + | The results of [3] and [4] are not the same. Thus, this is non-linear system. |
Revision as of 04:02, 12 September 2008
A linear function
we have seen is a function whose graph lies on a straight line, and which can be described by giving its slope and its y intercept
Linearity
If both system yield the same output function, this is called a linear system.
Prove
y(t)=2x(t)
[1]
x1(t)--->[system]---->y1(t)=2x1(t)---->*a---(1) a*2*x1(t)
x2(t)--->[system]---->y2(t)=2x2(t)---->*b---(2) b*2*x2(t)
(1)+(2)= 2ax1(t)+2bx2(t)
[2]
x1(t)--->*a---(3) a*x1(t)
x2(t)--->*b---(4) b*x2(t)
(3)+(4)=a*x1(t)+b*x2(t) ---->[system]---->2(a*x1(t)+b*x2(t))=2ax1(t)+2bx1(t)
The results of [1] and [2] are the same. Thus, this is linear system.
y(t)=x(t)^2
[3]
x1(t)--->[system]---->y1(t)=x1(t)^2---->*a---(5)a*x1(t)^2
x2(t)--->[system]---->y2(t)=x2(t)^2---->*b---(6)b*x2(t)^2
(5)+(6)= a*x1(t)^2+b*x2(t)^2
[4]
x1(t)--->*a---(7)a*x1(t)
x2(t)--->*b---(8)b*x2(t)
(7)+(8)=a*x1(t)+b*x2(t) ---->[system]---->(a*x1(t)+b*x2(t))^2
The results of [3] and [4] are not the same. Thus, this is non-linear system.