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x(t)=sin(t) from 0 to 8*pi
 
x(t)=sin(t) from 0 to 8*pi
  
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Revision as of 11:34, 12 September 2008

Periodic Function

I chose the function that Nicholas Browdues has used in the previous Homework 1 assignment as my reference signal. x(t)=sin(t) from 0 to 8*pi

Thing2 ECE301Fall2008mboutin.jpg

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