(Part 1)
(Part 1)
Line 11: Line 11:
 
<math>\,y[n]=x[0.1n]=2cos(\frac{2\pi n}{10})\,</math>
 
<math>\,y[n]=x[0.1n]=2cos(\frac{2\pi n}{10})\,</math>
  
would be periodic, since
+
is periodic, since
  
<math>\,y[n]=y[n+10N], \forall N\in Z\,</math>
+
<math>\,\exists N\in Z\,</math> such that <math>\,y[n]=y[n+N], \forall n\in Z\,</math>
 +
 
 +
<math>\,2cos(\frac{2\pi n}{10})=2cos(\frac{2\pi n}{10}+\frac{2\pi N}{10})\,</math>
 +
 
 +
This is true when
 +
 
 +
<math>\,\frac{2\pi N}{10}=2\pi \,</math>
 +
 
 +
<math>\,N=10\,</math>
  
  
Line 29: Line 37:
  
 
<math>\,z[n]=z[n+kN], \forall N\in Z\,</math>
 
<math>\,z[n]=z[n+kN], \forall N\in Z\,</math>
 
  
 
This can be seen in the following plot (notice how the values do not line up horizontally):
 
This can be seen in the following plot (notice how the values do not line up horizontally):

Revision as of 12:44, 11 September 2008

Part 1

The function was chosen at random from HW1: HW1.4 Hang Zhang - Periodic vs Non-period Functions_ECE301Fall2008mboutin

$ \,x(t)=2cos(2\pi t)\, $


Periodic Signal in DT:

If $ x(t) $ is sampled at $ period=0.1 $, the function

$ \,y[n]=x[0.1n]=2cos(\frac{2\pi n}{10})\, $

is periodic, since

$ \,\exists N\in Z\, $ such that $ \,y[n]=y[n+N], \forall n\in Z\, $

$ \,2cos(\frac{2\pi n}{10})=2cos(\frac{2\pi n}{10}+\frac{2\pi N}{10})\, $

This is true when

$ \,\frac{2\pi N}{10}=2\pi \, $

$ \,N=10\, $


This can be seen in the following plot (notice how the values lines up horizontally):

Jkubasci dt periodic ECE301Fall2008mboutin.jpg

Non-Periodic Signal in DT:

However, if $ x(t) $ is sampled at $ period=1/2\pi $, the function

$ \,z[n]=x[\frac{n}{2\pi}]=2cos(n)\, $

Is not periodic in DT, since is no integer $ k\in Z $ such that

$ \,z[n]=z[n+kN], \forall N\in Z\, $

This can be seen in the following plot (notice how the values do not line up horizontally):

Jkubasci dt nonperiodic ECE301Fall2008mboutin.jpg

Part 2

Alumni Liaison

Sees the importance of signal filtering in medical imaging

Dhruv Lamba, BSEE2010