(New page: == 6.(A) == This is not time-invariant.<br> 1. input(<math>/delta[n-k]</math>) -> system -> time delay -> output : <math>(k+1)^2/delta[n-(k+2)]</math><br> 2. input(<math>/delta[n-k]</mat...) |
(→6.(B)) |
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This is not time-invariant.<br> | This is not time-invariant.<br> | ||
| − | 1. input(<math>/delta[n-k]</math>) -> system -> time delay -> output : <math>(k+1)^2 | + | 1. input(<math>/delta[n-k]</math>) -> system -> time delay (1) -> output : <math>(k+1)^2\delta[n-(k+2)]</math><br> |
| − | 2. input(<math>/delta[n-k]</math>) -> time delay -> system -> output : <math>(k+2)^2 | + | 2. input(<math>/delta[n-k]</math>) -> time delay (1) -> system -> output : <math>(k+2)^2\delta[n-(k+2)]</math><br> |
The output signals are different each other. So this is not time-invariant. | The output signals are different each other. So this is not time-invariant. | ||
| + | |||
| + | |||
| + | == 6.(B) == | ||
| + | Because of assuming this system is linear, the input should be x[n]. | ||
Latest revision as of 17:50, 10 September 2008
6.(A)
This is not time-invariant.
1. input($ /delta[n-k] $) -> system -> time delay (1) -> output : $ (k+1)^2\delta[n-(k+2)] $
2. input($ /delta[n-k] $) -> time delay (1) -> system -> output : $ (k+2)^2\delta[n-(k+2)] $
The output signals are different each other. So this is not time-invariant.
6.(B)
Because of assuming this system is linear, the input should be x[n].
