(Proof)
(Proof)
 
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A CT non-periodic function: <br><math>\,y(t)=t</math>
 
A CT non-periodic function: <br><math>\,y(t)=t</math>
 
===Proof===
 
===Proof===
If the function is periodic, then there must exist a non-zero ''T'', that makes <math>y(t+T)=y(t)</math>, and there is no such number except 0 to satisfy the function <math>y(t)=t</math>.
+
If the function is periodic, then there must exist a non-zero ''T'', that makes <math>y(t+T)=y(t)</math>, and there is no such number except 0 to satisfy the function <math>y(t)=t</math>. Therefore, the function is non-periodic.

Latest revision as of 17:37, 5 September 2008

Periodic Function

A CT periodic function: $ \,y(t)=sin(t) $

Proof

To prove a function is periodic first you have to know the definition of a periodic fucntion
A periodic function is a function that repeats its values after some definite period has been added to its independent variable. This property is called periodicity.

Let's say we have:

$ \,y(t+T)=sin(t+T) $, $ \,T=2\pi $

Therefore, $ \,sin(t+T)=sin(t+2\pi) $

and $ \,sin(t+2\pi)=sin(t) $

The function repeats itself in a certain period which is $ 2\pi $ so it's a periodic function.

Non-periodic Function

A CT non-periodic function:
$ \,y(t)=t $

Proof

If the function is periodic, then there must exist a non-zero T, that makes $ y(t+T)=y(t) $, and there is no such number except 0 to satisfy the function $ y(t)=t $. Therefore, the function is non-periodic.

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