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==Coordinate Conversions for the Laplace Operator==
 
==Coordinate Conversions for the Laplace Operator==
  
It is most common to use the Laplace Operator <math>\Delta<math> in three-dimensions, as that is the dimensionality of our physical universe. Thus, the Laplace Operator is often used in 3-D Cartesian coordinates, cylindrical coordinates, and spherical coordinates.
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It is most common to use the Laplace Operator <math>\Delta</math> in three-dimensions, as that is the dimensionality of our physical universe. Thus, the Laplace Operator is often used in 3-D Cartesian coordinates, cylindrical coordinates, and spherical coordinates.
 +
 
 +
In 3-D Cartesian coordinates, the Laplace Operator is:
  
 
<math>
 
<math>
 
\Delta f=\frac{\partial^{2} f}{\partial x^{2}}+\frac{\partial^{2} f}{\partial y^{2}}+\frac{\partial^{2} f}{\partial z^{2}}\
 
\Delta f=\frac{\partial^{2} f}{\partial x^{2}}+\frac{\partial^{2} f}{\partial y^{2}}+\frac{\partial^{2} f}{\partial z^{2}}\
<\math>
+
</math>
 +
 
 +
The basis for this conversion is, in the opinion of the authors, quite clear. The dot product of the vectors: <math> \Bigg[\frac{\partial f}{\partial x}, \frac{\partial f}{\partial y},\frac{\partial f}{\partial z}\Bigg] </math> and <math> \left[\begin{array}{l}
 +
\frac{\partial}{\partial x} \\
 +
\frac{\partial}{\partial y} \\
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\frac{\partial}{\partial z}
 +
\end{array}\right] </math> will of course be <math> \frac{\partial^{2} f}{\partial x^{2}}+\frac{\partial^{2} f}{\partial y^{2}}+\frac{\partial^{2} f}{\partial z^{2}}\ </math>.
 +
 
 +
It became clear to the authors that the derivations for cylindrical and spherical coordinates are outside of their field of ability. However, their derivations are below, and if so interested, the reader can refer to the link titled "Laplacian Derivations in Cylindrical and Spherical Coordinates" in the section "Links for Further Reading".
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 +
In cylindrical coordinates, the Laplace Operator is:
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 +
<math>
 +
\Delta f=\frac{1}{\rho} \frac{\partial}{\partial \rho}\left(\rho \frac{\partial f}{\partial \rho}\right)+\frac{1}{\rho^{2}} \frac{\partial^{2} f}{\partial \varphi^{2}}+\frac{\partial^{2} f}{\partial z^{2}}
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</math>
 +
 
 +
In spherical coordinates, the Laplace Operator is:
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 +
<math>
 +
\Delta f=\frac{1}{r} \frac{\partial^{2}}{\partial r^{2}}(r f)+\frac{1}{r^{2} \sin \theta} \frac{\partial}{\partial \theta}\left(\sin \theta \frac{\partial f}{\partial \theta}\right)+\frac{1}{r^{2} \sin ^{2} \theta} \frac{\partial^{2} f}{\partial \varphi^{2}}
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</math>
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Latest revision as of 14:53, 6 December 2020

Coordinate Conversions for the Laplace Operator

It is most common to use the Laplace Operator $ \Delta $ in three-dimensions, as that is the dimensionality of our physical universe. Thus, the Laplace Operator is often used in 3-D Cartesian coordinates, cylindrical coordinates, and spherical coordinates.

In 3-D Cartesian coordinates, the Laplace Operator is:

$ \Delta f=\frac{\partial^{2} f}{\partial x^{2}}+\frac{\partial^{2} f}{\partial y^{2}}+\frac{\partial^{2} f}{\partial z^{2}}\ $

The basis for this conversion is, in the opinion of the authors, quite clear. The dot product of the vectors: $ \Bigg[\frac{\partial f}{\partial x}, \frac{\partial f}{\partial y},\frac{\partial f}{\partial z}\Bigg] $ and $ \left[\begin{array}{l} \frac{\partial}{\partial x} \\ \frac{\partial}{\partial y} \\ \frac{\partial}{\partial z} \end{array}\right] $ will of course be $ \frac{\partial^{2} f}{\partial x^{2}}+\frac{\partial^{2} f}{\partial y^{2}}+\frac{\partial^{2} f}{\partial z^{2}}\ $.

It became clear to the authors that the derivations for cylindrical and spherical coordinates are outside of their field of ability. However, their derivations are below, and if so interested, the reader can refer to the link titled "Laplacian Derivations in Cylindrical and Spherical Coordinates" in the section "Links for Further Reading".

In cylindrical coordinates, the Laplace Operator is:

$ \Delta f=\frac{1}{\rho} \frac{\partial}{\partial \rho}\left(\rho \frac{\partial f}{\partial \rho}\right)+\frac{1}{\rho^{2}} \frac{\partial^{2} f}{\partial \varphi^{2}}+\frac{\partial^{2} f}{\partial z^{2}} $

In spherical coordinates, the Laplace Operator is:

$ \Delta f=\frac{1}{r} \frac{\partial^{2}}{\partial r^{2}}(r f)+\frac{1}{r^{2} \sin \theta} \frac{\partial}{\partial \theta}\left(\sin \theta \frac{\partial f}{\partial \theta}\right)+\frac{1}{r^{2} \sin ^{2} \theta} \frac{\partial^{2} f}{\partial \varphi^{2}} $

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Alumni Liaison

Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva