(17 intermediate revisions by the same user not shown)
Line 19: Line 19:
 
August 2013
 
August 2013
 
</center>
 
</center>
 +
----
 +
[[ECE-QE_CE1-2013|Back to QE CE question 2, August 2013]]
 +
----
 +
'''Problem 2.'''
 +
 +
Suppose your company develops and manages construction of boat launching docks along a downstream stretch of the Wabash river. This stretch runs north-south for <math>L</math> miles within the State of Indiana. The possible sites for docks are given by numbers <math>x_1 < x_2 < x_3 < ... < x_n</math>, each in the interval <math>[0,L]</math>, specifying their positions in miles measured from the northern end of this stretch of the Wabash river. If your company constructs a dock at position <math>x_i</math>, it receives a revenue of <math>r_i >0</math>. Regulations imposed by the Indiana Department of Water Resource Management require that no two docks should be built within a distance of less than 5 miles from each other. Your company plans to construct docks at a subset of the potential sites so as to maximize the total revenue., subject to this distance restriction. For example, suppose <math>L=20</math> and <math>n=5</math> with potential sites given by <math>\lbrace x_1, x_2, x_3, x_4, x_5 \rbrace = \lbrace 6,7,12,13,14\rbrace</math> and <math>\lbrace r_1, r_2, r_3, r_4, r_5 \rbrace = \lbrace 5,6,5,3,1\rbrace</math>. Then the best solution is to construct docks at locations <math>x_1</math> and <math>x_3</math> to achieve a revenue of 10.
 +
Describe a dynamic programming formulation to find a solution for this optimization problem. Compute the complexity of solving your dynamic programming formulation of this problem.
 +
 +
----
 +
Share and discuss your solution below.
 
----
 
----
 
===Solution 1===
 
===Solution 1===
This problem can be solved using dynamic programming. For each docks <math>x_i</math>, compute the revenue from <math>x_1</math> to <math>x_i</math>, if <math>x_i</math> is selected, and the remaining docks <math>x_{i+1}</math> to <math>x_n</math>, if <math>x_i</math> is not selected.  
+
This problem can be solved using dynamic programming. For each dock <math>x_i</math>, compute the revenue from <math>x_1</math> to <math>x_i</math>, if <math>x_i</math> is selected, and the revenue for remaining docks <math>x_{i+1}</math> to <math>x_n</math>, if <math>x_i</math> is not selected.  
  
 
<math>R[i]</math>: denote the total revenue using only sites <math>x_1, \dots , x_i</math>.
 
<math>R[i]</math>: denote the total revenue using only sites <math>x_1, \dots , x_i</math>.
Line 30: Line 40:
 
The pseudo code for dynamic programming is showing below. Note we use bottom up to fill up <math>R</math> and <math>L</math>.
 
The pseudo code for dynamic programming is showing below. Note we use bottom up to fill up <math>R</math> and <math>L</math>.
  
[[File:Dynamic.png|800px|Pseudo code for dynamic programming]]
+
[[File:Dynamic.png|800px|Pseudo code for dynamic programming 1]]
 +
 
 +
In the end of the program, <math>R[n]</math> will be the maximum revenue, and <math>L[n]</math>, <math>L[L[n]]</math>, ... will be the indices of locations to choose.
 +
 
 +
----
 +
===Solution 2===
 +
Sub-problem: after picking one location <math>q</math>, need to find the max revenue of the remaining docks whose location is greater than 5 miles away from <math>q</math>.
 +
Bottom-up-dock-revenue.
 +
 
 +
Let <math>r[0...n]</math> be a new array, <math>r[0]=0</math>. The pseudo code is show below:<br>
 +
[[File:Dynamic2.png|400px|Pseudo code for dynamic programming 2]]
 +
 
 +
<br>
 +
 
 +
<font color="red"><u>'''Comments on Solution 2:'''</u>
  
In the end of the program, <math>R[n]</math> will be the maximum revenue, and L[n], L[L[n]], ... will be the indices of locations to choose.
+
Using dynamic program and bottom up to fill in the solution is a good approach.
 +
For each dock, we need to find the greater of either selecting this dock and have the revenue for this dock, while any other docks within 5 miles will not be selected; or not selecting the dock and having the remaining docks that includes the docks within 5 miles away to achieve their best revenue.  In this solution, it is not clear what <math>p[i]</math> is represent for. In addition, the docks what within 5 miles away could be on both sides. This solution only consider one side.
 +
<br>
  
 +
----
  
 
[[ECE-QE_CE1-2013|Back to QE CE question 2, August 2013]]
 
[[ECE-QE_CE1-2013|Back to QE CE question 2, August 2013]]
  
 
[[ECE_PhD_Qualifying_Exams|Back to ECE Qualifying Exams (QE) page]]
 
[[ECE_PhD_Qualifying_Exams|Back to ECE Qualifying Exams (QE) page]]

Latest revision as of 15:09, 23 August 2017


ECE Ph.D. Qualifying Exam

Computer Engineering(CE)

Question 1: Algorithms

August 2013


Back to QE CE question 2, August 2013


Problem 2.

Suppose your company develops and manages construction of boat launching docks along a downstream stretch of the Wabash river. This stretch runs north-south for $ L $ miles within the State of Indiana. The possible sites for docks are given by numbers $ x_1 < x_2 < x_3 < ... < x_n $, each in the interval $ [0,L] $, specifying their positions in miles measured from the northern end of this stretch of the Wabash river. If your company constructs a dock at position $ x_i $, it receives a revenue of $ r_i >0 $. Regulations imposed by the Indiana Department of Water Resource Management require that no two docks should be built within a distance of less than 5 miles from each other. Your company plans to construct docks at a subset of the potential sites so as to maximize the total revenue., subject to this distance restriction. For example, suppose $ L=20 $ and $ n=5 $ with potential sites given by $ \lbrace x_1, x_2, x_3, x_4, x_5 \rbrace = \lbrace 6,7,12,13,14\rbrace $ and $ \lbrace r_1, r_2, r_3, r_4, r_5 \rbrace = \lbrace 5,6,5,3,1\rbrace $. Then the best solution is to construct docks at locations $ x_1 $ and $ x_3 $ to achieve a revenue of 10. Describe a dynamic programming formulation to find a solution for this optimization problem. Compute the complexity of solving your dynamic programming formulation of this problem.


Share and discuss your solution below.


Solution 1

This problem can be solved using dynamic programming. For each dock $ x_i $, compute the revenue from $ x_1 $ to $ x_i $, if $ x_i $ is selected, and the revenue for remaining docks $ x_{i+1} $ to $ x_n $, if $ x_i $ is not selected.

$ R[i] $: denote the total revenue using only sites $ x_1, \dots , x_i $.

$ L[i] $: denote $ i $ with the greatest value such that $ x_i $ is used for the solution in $ R[i] $.

Initially, $ L[<=0]=0 $, $ R[<=0]=0 $, $ x_0 = -\infty $, $ r_0=0 $. The pseudo code for dynamic programming is showing below. Note we use bottom up to fill up $ R $ and $ L $.

Pseudo code for dynamic programming 1

In the end of the program, $ R[n] $ will be the maximum revenue, and $ L[n] $, $ L[L[n]] $, ... will be the indices of locations to choose.


Solution 2

Sub-problem: after picking one location $ q $, need to find the max revenue of the remaining docks whose location is greater than 5 miles away from $ q $. Bottom-up-dock-revenue.

Let $ r[0...n] $ be a new array, $ r[0]=0 $. The pseudo code is show below:
Pseudo code for dynamic programming 2


Comments on Solution 2:

Using dynamic program and bottom up to fill in the solution is a good approach. For each dock, we need to find the greater of either selecting this dock and have the revenue for this dock, while any other docks within 5 miles will not be selected; or not selecting the dock and having the remaining docks that includes the docks within 5 miles away to achieve their best revenue. In this solution, it is not clear what $ p[i] $ is represent for. In addition, the docks what within 5 miles away could be on both sides. This solution only consider one side.


Back to QE CE question 2, August 2013

Back to ECE Qualifying Exams (QE) page

Alumni Liaison

Basic linear algebra uncovers and clarifies very important geometry and algebra.

Dr. Paul Garrett