(New page: Outline Introduction Derivation Example Conclusion Introduction Hello! My name is Ryan Johnson! You might be wondering was a slecture is! A slecture is a student lecture that gives a br...)
 
 
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Outline  
 
Outline  
Introduction
 
Derivation
 
Example
 
Conclusion
 
  
Introduction Hello! My name is Ryan Johnson! You might be wondering was a slecture is! A slecture is a student lecture that gives a brief overview about a particular topic! In this slecture, I will discuss the relationship between an original signal and a continuous time sampling of that original signal. We will also take a look at how this relationship translates to the frequency domain. Derivation  
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<br>
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Introduction<br>Derivation<br>Example<br>Conclusion<br>References
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<br>
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Introduction
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Hello! My name is Ryan Johnson! You might be wondering what a slecture is! A slecture is a student lecture that gives a brief overview about a particular topic! In this slecture, I will discuss the relationship between an original signal, x(t), and a sampling of that original signal, x_s(t). We will also take a look at how this relationship translates to the frequency domain, (X(f) & X_s(f)).  
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Derivation  
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F = Fourier transform
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<div style="margin-left: 3em;">
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<math>
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\begin{align}
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comb_T(x(t)) &= x(t) \times p_T(t) &= x_s(t)\\
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\end{align}
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</math> The comb of a signal is equal to the signal multiplied by an impulse train which is equal to the sampled signal. Essentially, the comb is grabbing points on the graph x(t) at a set interval, T. <math>
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\begin{align}
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X_s(f) &= F(x_s(t)) = F(comb_T(x(t))\\
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&= F(x(t)p_T(t))\\
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&= X(f) * F(p_T(f)\\
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\end{align}
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</math> Multiplication in time is equal to convolution in frequency. <br> <math>
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\begin{align}
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X_s(f)&= X(f)*\frac{1}{T}\sum_{n = -\infty}^\infty \delta(f-\frac{n}{T})\\
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\end{align}
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</math> definition of the Fourier transform of an impulse train.
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<br>
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<div style="margin-left: 3em;">
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<math>
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\begin{align}
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&= \frac{1}{T}X(f)*p_\frac{1}{T}(f)\\
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&= \frac{1}{T}rep_\frac{1}{T}X(f)\\
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\end{align}
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</math> The result is a repetition of the Fourier transformed signal.
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</div>
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<font size="size"></font>
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<br>
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Example  
 
Example  
Conclusion So the relationship between X(f) and Xs(f) is that Xs(f) is a a rep of X(f) in frequency domain with period of and magnitude scaled by . the relationship between X(f) and Xd(ω) is that Xd(ω) is also a a rep of X(f) in frequency domain with period 2π and magnitude is also scaled by , but the frequency is scaled by 2πT
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[[Image:Johns637_3.jpg]]
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<br>
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Conclusion  
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Xs(f) is a rep of X(f) in the frequency domain with amplitude of 1/T and period of 1/T.
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Questions
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<br>
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If you have any questions, comments, etc. please post them on [[Slecture_Topic_7_Ryancomments|this page]].
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References
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[1] Mireille Boutin, "ECE 438 Digital Signal Processing with Applications," Purdue University. October 6, 2014.
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[[2014_Fall_ECE_438_Boutin_digital_signal_processing_slectures|Back to ECE438 slectures, Fall 2014]]

Latest revision as of 08:57, 14 March 2015

Outline


Introduction
Derivation
Example
Conclusion
References


Introduction

Hello! My name is Ryan Johnson! You might be wondering what a slecture is! A slecture is a student lecture that gives a brief overview about a particular topic! In this slecture, I will discuss the relationship between an original signal, x(t), and a sampling of that original signal, x_s(t). We will also take a look at how this relationship translates to the frequency domain, (X(f) & X_s(f)).

Derivation

F = Fourier transform

$ \begin{align} comb_T(x(t)) &= x(t) \times p_T(t) &= x_s(t)\\ \end{align} $ The comb of a signal is equal to the signal multiplied by an impulse train which is equal to the sampled signal. Essentially, the comb is grabbing points on the graph x(t) at a set interval, T. $ \begin{align} X_s(f) &= F(x_s(t)) = F(comb_T(x(t))\\ &= F(x(t)p_T(t))\\ &= X(f) * F(p_T(f)\\ \end{align} $ Multiplication in time is equal to convolution in frequency.
$ \begin{align} X_s(f)&= X(f)*\frac{1}{T}\sum_{n = -\infty}^\infty \delta(f-\frac{n}{T})\\ \end{align} $ definition of the Fourier transform of an impulse train.

$ \begin{align} &= \frac{1}{T}X(f)*p_\frac{1}{T}(f)\\ &= \frac{1}{T}rep_\frac{1}{T}X(f)\\ \end{align} $ The result is a repetition of the Fourier transformed signal.


Example Johns637 3.jpg

Conclusion

Xs(f) is a rep of X(f) in the frequency domain with amplitude of 1/T and period of 1/T.

Questions

If you have any questions, comments, etc. please post them on this page.

References
[1] Mireille Boutin, "ECE 438 Digital Signal Processing with Applications," Purdue University. October 6, 2014.


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