(New page: For question 1, is omega_c > 0 the same as "there are no conditions set"?)
 
 
(2 intermediate revisions by 2 users not shown)
Line 1: Line 1:
 
For question 1, is omega_c > 0 the same as "there are no conditions set"?
 
For question 1, is omega_c > 0 the same as "there are no conditions set"?
 +
:no, because it excludes <math>\omega_c=0</math>. The carrier frequency <math>\omega_c=0</math> could be equal to zero, in which case, the signal would simply be multiplied by one. Of course, one can then recover the signal! -pm
 +
 +
For question 1b), should <math class="inline">e^{-j(\omega_c+\theta_c)}</math> be <math class="inline">e^{-j(\omega_ct+\theta_c)}</math> ?
 +
:Yes, you are right. The correction has been made. -pm
 +
----

Latest revision as of 09:04, 19 April 2011

For question 1, is omega_c > 0 the same as "there are no conditions set"?

no, because it excludes $ \omega_c=0 $. The carrier frequency $ \omega_c=0 $ could be equal to zero, in which case, the signal would simply be multiplied by one. Of course, one can then recover the signal! -pm

For question 1b), should $ e^{-j(\omega_c+\theta_c)} $ be $ e^{-j(\omega_ct+\theta_c)} $ ?

Yes, you are right. The correction has been made. -pm

Alumni Liaison

Basic linear algebra uncovers and clarifies very important geometry and algebra.

Dr. Paul Garrett