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| − | I think it is C(11,7)/C(80, | + | I think it is C(11,7)/C(80,7) since C(11,7) calculates the ways to choose 7 of the 11 winning numbers while C(80,7) calculates all the possible sets of 7 winning numbers. |
Latest revision as of 09:57, 4 October 2008
Hey! I was looking at this one, and kind of confused on how to approach it, right now I have (80x79x78x77x76x75x74)/C(80,11) = 1/26122320. But I do not think that this is correct, please help!
On the top I put number of ways to pick 7 numbers which will result in winning out of the 11 which could result in winning.
On bottom I put all possible numbers (80,11)
I think it is C(11,7)/C(80,7) since C(11,7) calculates the ways to choose 7 of the 11 winning numbers while C(80,7) calculates all the possible sets of 7 winning numbers.
