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| − | + | =How to obtain the CTFT of a unit impulse formula in terms of f in hertz (from the formula in terms of <math>\omega</math>) = | |
| − | + | ||
| − | + | Recall: | |
| − | + | ||
| − | + | <math> \mathcal{X}(\omega)=1 </math> | |
| − | | | + | |
| + | To obtain X(f), use the substitution | ||
| + | |||
| + | <math>\omega= 2 \pi f </math>. | ||
| + | |||
| + | More specifically | ||
| + | |||
| + | <math>X(f)=\mathcal{X}(2\pi f)=1\ </math> | ||
| + | |||
| + | ---- | ||
| + | [[ECE438_HW1_Solution|Back to Table]] | ||
Latest revision as of 10:02, 15 September 2010
How to obtain the CTFT of a unit impulse formula in terms of f in hertz (from the formula in terms of $ \omega $)
Recall:
$ \mathcal{X}(\omega)=1 $
To obtain X(f), use the substitution
$ \omega= 2 \pi f $.
More specifically
$ X(f)=\mathcal{X}(2\pi f)=1\ $
