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'''Problem 18''' (A problem with problem 18). By checking the inequality for <math> n=1 </math>  
 
'''Problem 18''' (A problem with problem 18). By checking the inequality for <math> n=1 </math>  
 
one finds that <math>{}={}</math> holds rather than <math>{} >{} </math>. <br><br> In fact, the  
 
one finds that <math>{}={}</math> holds rather than <math>{} >{} </math>. <br><br> In fact, the  
inequality holds for <math>n=2</math>. In your assignment, you can either use <math>\ge</math> or prove that the <math> > </math> holds for <math>n\ge 2</math>.
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inequality holds for <math>n=2</math>. In your assignment, you can either replace ">" with "<math>\ge</math>" or prove that the inequality <math> > </math> holds for <math>n\ge 2</math>.
  
  
 
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Latest revision as of 14:25, 18 January 2010

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Problem 18 (A problem with problem 18). By checking the inequality for $ n=1 $ one finds that $ {}={} $ holds rather than $ {} >{} $.

In fact, the inequality holds for $ n=2 $. In your assignment, you can either replace ">" with "$ \ge $" or prove that the inequality $ > $ holds for $ n\ge 2 $.



Alumni Liaison

Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett