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Euler's identity
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<math>  e^{j \pi} + 1 = 0, \,\! </math>
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Euler's formula
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<math>    e^{jx} = \cos x + j \sin x \,\! </math>
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<math>        \cos x = \mathrm{Re}\{e^{jx}\} ={e^{jx} + e^{-jx} \over 2}</math>
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<math>  \sin x = \mathrm{Im}\{e^{jx}\} ={e^{jx} - e^{-jx} \over 2i}.  </math>
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<math>    \cos(x) = {e^{-jx} + e^{jx} \over 2}</math>
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<math>    \sin(x) = {e^{-jx} - e^{jx} \over 2j} </math>

Latest revision as of 19:40, 22 July 2009

Euler's identity

$ e^{j \pi} + 1 = 0, \,\! $

Euler's formula

$ e^{jx} = \cos x + j \sin x \,\! $

$ \cos x = \mathrm{Re}\{e^{jx}\} ={e^{jx} + e^{-jx} \over 2} $

$ \sin x = \mathrm{Im}\{e^{jx}\} ={e^{jx} - e^{-jx} \over 2i}. $

$ \cos(x) = {e^{-jx} + e^{jx} \over 2} $

$ \sin(x) = {e^{-jx} - e^{jx} \over 2j} $

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To all math majors: "Mathematics is a wonderfully rich subject."

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