(New page: Okay, I'm having a bit of trouble with this one. Neither the root test nor the ratio test is pretty. Should I try to use a different test? It's kind late, so my thoughts are a bit scram...) |
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Okay, I'm having a bit of trouble with this one. Neither the root test nor the ratio test is pretty. Should I try to use a different test? It's kind late, so my thoughts are a bit scrambled. I think I'm gonna try to rewrite the sum and see what that gets me. | Okay, I'm having a bit of trouble with this one. Neither the root test nor the ratio test is pretty. Should I try to use a different test? It's kind late, so my thoughts are a bit scrambled. I think I'm gonna try to rewrite the sum and see what that gets me. | ||
| − | <math>\frac{n!}{n^n}=\frac{(n-1)!}{n^{n-1}}<math> | + | <math>\frac{n!}{n^n}=\frac{(n-1)!}{n^{n-1}}</math> |
| − | Don't know what that will do, but we'll see. | + | Don't know what that will do, but we'll see. [[User:Jhunsber|His Awesomeness, Josh Hunsberger]] |
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| + | Nevermind, I figured it out. You just have to do a second comparison between the resultant denominator in the limit with a simpler version, and show how that the limit is less than one. If you have difficulty, just give me a shout | ||
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| + | [[User:Jhunsber|His Awesomeness, Josh Hunsberger]] | ||
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| + | I got that it diverged because the limit went to infinity...maybe I'll just ask about it in class and see where I went wrong, if I am wrong, which is more than likely. --[[User:Reckman|Randy Eckman]] 12:19, 5 November 2008 (UTC) | ||
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| + | Yeah, well I must have been really tired because the way I did it I had that <math>(n+1)!<n!</math> which is absolutely ludicrous. Then I made another mistake after that, but it doesn't matter. Bell explained it really well and i knew I had seen that problem somewhere else, I just forgot about it. [[User:Jhunsber|His Awesomeness, Josh Hunsberger]] | ||
Latest revision as of 17:45, 5 November 2008
Okay, I'm having a bit of trouble with this one. Neither the root test nor the ratio test is pretty. Should I try to use a different test? It's kind late, so my thoughts are a bit scrambled. I think I'm gonna try to rewrite the sum and see what that gets me.
$ \frac{n!}{n^n}=\frac{(n-1)!}{n^{n-1}} $
Don't know what that will do, but we'll see. His Awesomeness, Josh Hunsberger
Nevermind, I figured it out. You just have to do a second comparison between the resultant denominator in the limit with a simpler version, and show how that the limit is less than one. If you have difficulty, just give me a shout
His Awesomeness, Josh Hunsberger
I got that it diverged because the limit went to infinity...maybe I'll just ask about it in class and see where I went wrong, if I am wrong, which is more than likely. --Randy Eckman 12:19, 5 November 2008 (UTC)
Yeah, well I must have been really tired because the way I did it I had that $ (n+1)!<n! $ which is absolutely ludicrous. Then I made another mistake after that, but it doesn't matter. Bell explained it really well and i knew I had seen that problem somewhere else, I just forgot about it. His Awesomeness, Josh Hunsberger
