(New page: What I ended up doing, in response to Adam's message, is figuring that: <math>x_1[n] = -x_1[-n]</math> and <math>x_2[n] = x_2[-n] </math> and then defined <math>(x_1[n])(x_2[n])</math> as...)
 
 
Line 6: Line 6:
 
Multiplying the redefined <math>x_1[n]</math> and <math>x_2[n]</math> I got <math>-(x_1[-n](x_2[-n]))</math> which resembles very closely -y[-n].
 
Multiplying the redefined <math>x_1[n]</math> and <math>x_2[n]</math> I got <math>-(x_1[-n](x_2[-n]))</math> which resembles very closely -y[-n].
 
From there I declared the function odd.
 
From there I declared the function odd.
 +
 +
Back to [[Homework_1]]

Latest revision as of 14:12, 23 June 2009

What I ended up doing, in response to Adam's message, is figuring that:

$ x_1[n] = -x_1[-n] $ and $ x_2[n] = x_2[-n] $ and then defined $ (x_1[n])(x_2[n]) $ as y[n]

Multiplying the redefined $ x_1[n] $ and $ x_2[n] $ I got $ -(x_1[-n](x_2[-n])) $ which resembles very closely -y[-n]. From there I declared the function odd.

Back to Homework_1

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood