Difference between revisions of "Page 563: Problem 11 MA181Fall2008bell" - Rhea

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-* I didn't get the right answer according to the back of the book. I got:
-<math>x + 4 = Ax + A + Bx - 6B = (A + B)x + A - 6B</math>
-Meaning:
-<math>A + B = 1</math>
-and
-<math>A - 6B = 4</math>
-So, <math>A = \frac{10}{7}</math>  and  <math>B = -\frac{3}{7}</math>
-The answer in the back of the book is
-<math>\frac{1}{7}\ln{\abs{(x+6)^2(x-1)^5}}+C</math>

Latest revision as of 12:06, 13 October 2008