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A) <math> 1 + j\sqrt{3}</math> | A) <math> 1 + j\sqrt{3}</math> | ||
| − | <math> r = \sqrt{1^2 + \sqrt{3}^2}</math> | + | <math> r = \sqrt{1^2 + \sqrt{3}^2} = \sqrt{4} = 2</math> |
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| + | <math>\theta = arctan(\sqrt{3}/1) = arctan(\sqrt{3}) = \frac{\pi}{3}</math> | ||
| + | |||
| + | Therefore the polar form of this complex number is: <math>2e^{j\frac{\pi}{3}}</math> | ||
| + | |||
| + | B) <math> -5 </math> | ||
| + | |||
| + | <math> r = 5 </math> | ||
| + | |||
| + | <math> \theta = \pi </math> | ||
| + | |||
| + | Therefore the polar form of this complex number is: <math>5e^{j\pi}</math> | ||
| + | |||
| + | F) <math> (1 + j)^{5} </math> | ||
| + | |||
| + | <math> r = \sqrt{1^2 + 1^2} = \sqrt{2} </math> | ||
| + | |||
| + | <math> \theta = \frac{\pi}{4} </math> | ||
| + | |||
| + | <math> (1 + j) = \sqrt{2}e^{j\frac{\pi}{4}} </math> | ||
| + | |||
| + | <math> (1 + j)^{5} = (\sqrt{2}e^{j\frac{\pi}{4}})^{5} = 2^{\frac{5}{2}}e^{j\frac{5\pi}{4}} = 4\sqrt{2}e^{j(\pi + \frac{\pi}{4})} =4\sqrt{2}e^{j\pi}e^{j\frac{\pi}{4}} = -4(\sqrt{2}e^{j\frac{\pi}{4}}) = -4(1 + j)</math> | ||
| + | |||
| + | Therefore the polar form of this complex number is: <math> -4(\sqrt{2}e^{j\frac{\pi}{4}}) </math> | ||
| + | |||
| + | I) <math> \frac{1 + j\sqrt{3}}{\sqrt{3} + j} </math> | ||
| + | |||
| + | <math> r = 2 </math> | ||
| + | |||
| + | <math> Equation 1 = 1 + j\sqrt{3} => \theta_{1} = \frac{\pi}{3} </math> | ||
| + | |||
| + | <math> Equation 2 = \sqrt{3} + j => \theta_{2} = \frac{\pi}{6} </math> | ||
| + | |||
| + | <math> \frac{2e^{j\frac{\pi}{3}}}{2e^{j\frac{\pi}{6}}} = \frac{e^{j\frac{\pi}{3}}}{e^{j\frac{\pi}{6}}} = e^{j(\frac{\pi}{3} - \frac{\pi}{6})} = e^{j\frac{\pi}{6}}</math> | ||
| + | |||
| + | Therefore the polar form of this complex number is: <math> e^{j\frac{\pi}{6}}</math> | ||
Latest revision as of 00:33, 13 June 2008
Express each of the following complex numbers in polar form, and plot them in the complex plane, indicating the magnitude and angle of each number.
A) $ 1 + j\sqrt{3} $
$ r = \sqrt{1^2 + \sqrt{3}^2} = \sqrt{4} = 2 $
$ \theta = arctan(\sqrt{3}/1) = arctan(\sqrt{3}) = \frac{\pi}{3} $
Therefore the polar form of this complex number is: $ 2e^{j\frac{\pi}{3}} $
B) $ -5 $
$ r = 5 $
$ \theta = \pi $
Therefore the polar form of this complex number is: $ 5e^{j\pi} $
F) $ (1 + j)^{5} $
$ r = \sqrt{1^2 + 1^2} = \sqrt{2} $
$ \theta = \frac{\pi}{4} $
$ (1 + j) = \sqrt{2}e^{j\frac{\pi}{4}} $
$ (1 + j)^{5} = (\sqrt{2}e^{j\frac{\pi}{4}})^{5} = 2^{\frac{5}{2}}e^{j\frac{5\pi}{4}} = 4\sqrt{2}e^{j(\pi + \frac{\pi}{4})} =4\sqrt{2}e^{j\pi}e^{j\frac{\pi}{4}} = -4(\sqrt{2}e^{j\frac{\pi}{4}}) = -4(1 + j) $
Therefore the polar form of this complex number is: $ -4(\sqrt{2}e^{j\frac{\pi}{4}}) $
I) $ \frac{1 + j\sqrt{3}}{\sqrt{3} + j} $
$ r = 2 $
$ Equation 1 = 1 + j\sqrt{3} => \theta_{1} = \frac{\pi}{3} $
$ Equation 2 = \sqrt{3} + j => \theta_{2} = \frac{\pi}{6} $
$ \frac{2e^{j\frac{\pi}{3}}}{2e^{j\frac{\pi}{6}}} = \frac{e^{j\frac{\pi}{3}}}{e^{j\frac{\pi}{6}}} = e^{j(\frac{\pi}{3} - \frac{\pi}{6})} = e^{j\frac{\pi}{6}} $
Therefore the polar form of this complex number is: $ e^{j\frac{\pi}{6}} $
