(New page: <math>\theta </math> is uniform [0,1] supp. <math>\theta</math> = 1/3 MSE = E[ (<math>\theta</math> - 1/3)^2 ] = E[ <math>\theta</math>^2 - 2*(1/3)*<math>\theta</math> + (1/3)^2 ] = 1/3 ...)
 
 
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<math>\theta </math> is uniform [0,1]
 
<math>\theta </math> is uniform [0,1]
  
supp. <math>\theta</math> = 1/3
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E[ <math>\theta^2 </math> ] = <math>\int\limits_{0}^{1} \theta^2 d\theta </math>
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= 1/3
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supp. <math>\theta^{hat}</math> = 1/3
  
MSE = E[ (<math>\theta</math> - 1/3)^2 ] = E[ <math>\theta</math>^2 - 2*(1/3)*<math>\theta</math> + (1/3)^2 ]
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MSE = E[ (<math>\theta</math> - 1/3)^2 ] = E[ <math>\theta^2</math> - 2*(1/3)*<math>\theta</math> + (1/3)^2 ]
 
= 1/3 - 2(1/3)(1/2) + (1/3)^2 = (1/3)^2 = 1/9
 
= 1/3 - 2(1/3)(1/2) + (1/3)^2 = (1/3)^2 = 1/9
  
supp. instead <math>\theta</math> = 1/2
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supp. instead <math>\theta^{hat}</math> = 1/2
  
MSE = E[ (<math>\theta</math> - 1/2)^2 ] = E[ <math>\theta</math>^2 - 2*(1/3)*<math>\theta</math> + (1/4) ] = 1/3 - 1/2 + 1/4 = 1/12
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MSE = E[ (<math>\theta</math> - 1/2)^2 ] = E[ <math>\theta^2</math> - 2*(1/3)*<math>\theta</math> + (1/4) ] = 1/3 - 1/2 + 1/4 = 1/12
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Latest revision as of 12:41, 22 November 2011


$ \theta $ is uniform [0,1]

E[ $ \theta^2 $ ] = $ \int\limits_{0}^{1} \theta^2 d\theta $ = 1/3

supp. $ \theta^{hat} $ = 1/3

MSE = E[ ($ \theta $ - 1/3)^2 ] = E[ $ \theta^2 $ - 2*(1/3)*$ \theta $ + (1/3)^2 ] = 1/3 - 2(1/3)(1/2) + (1/3)^2 = (1/3)^2 = 1/9

supp. instead $ \theta^{hat} $ = 1/2

MSE = E[ ($ \theta $ - 1/2)^2 ] = E[ $ \theta^2 $ - 2*(1/3)*$ \theta $ + (1/4) ] = 1/3 - 1/2 + 1/4 = 1/12


Back to ECE302 Fall 2008 Prof. Sanghavi

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Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

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