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After that, you can get the answer "a" and "b".--[[User:Kim415|Kim415]] 09:55, 13 April 2009 (UTC) | After that, you can get the answer "a" and "b".--[[User:Kim415|Kim415]] 09:55, 13 April 2009 (UTC) | ||
| − | I believe this is correct. My understand was that you differentiate in terms of a. Then, you differentiate the original equation | + | I believe this is correct. My understand was that you differentiate in terms of a. Then, you differentiate the original equation (not the newly obtained one via the differentiation in terms of a) in terms of b. These two equations will present the classic, and easy-to-solve, case of two-equations-and-two-unknowns. From here on out, it is basic algebra. Oh, joy! I may be wrong, however, so do not take my word for it. Also, if anyone has a better idea, please, tell me. |
--[[User:vhsieh|vhsieh]] 11:08, 13 April 2009 (UTC) | --[[User:vhsieh|vhsieh]] 11:08, 13 April 2009 (UTC) | ||
Latest revision as of 07:12, 13 April 2009
a. On the problem hint, "differentiate" means to differentiate "a" and "b".
After that, you can get the answer "a" and "b".--Kim415 09:55, 13 April 2009 (UTC)
I believe this is correct. My understand was that you differentiate in terms of a. Then, you differentiate the original equation (not the newly obtained one via the differentiation in terms of a) in terms of b. These two equations will present the classic, and easy-to-solve, case of two-equations-and-two-unknowns. From here on out, it is basic algebra. Oh, joy! I may be wrong, however, so do not take my word for it. Also, if anyone has a better idea, please, tell me.
--vhsieh 11:08, 13 April 2009 (UTC)
