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in class we found the following:
 
in class we found the following:
  
<math>E[x] = \frac{a+b/2}</math>
+
<math>E[X] = \frac{a+b}{2}</math>
 +
 
 +
<math>E[X^2] = \frac{a^2+ab+b^2}{3}</math>
 +
 
 +
Thus using the formula for variance:
 +
 
 +
<math> Var(X) = E[X^2] - (E[X])^2 \!</math>
 +
 
 +
One can reduce the equation to your final answer.

Latest revision as of 12:17, 2 November 2008

The problem only asks for the variance of a uniform R.V. on the interval [a,b]

in class we found the following:

$ E[X] = \frac{a+b}{2} $

$ E[X^2] = \frac{a^2+ab+b^2}{3} $

Thus using the formula for variance:

$ Var(X) = E[X^2] - (E[X])^2 \! $

One can reduce the equation to your final answer.

Alumni Liaison

Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva