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-Allen Jarboe | -Allen Jarboe | ||
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+ | Does anyone know how to do this one? | ||
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+ | I don't completely understand this problem. Did somebody understand it well? | ||
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+ | -Nate Shafer |
Latest revision as of 18:39, 2 November 2008
The multiplicative set of F of non-zero elements forms a group under multiplication. Since it has n-1 elements it means x^(n-1) = 1 (property of groups
-Sarah Liszka
Does this work? I was looking and don't we need the group to be cyclic for that to work?
-Allen Jarboe
Does anyone know how to do this one?
I don't completely understand this problem. Did somebody understand it well?
-Nate Shafer