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=[[HW3_MA453Fall2008walther|HW3]], Chapter 3, Problem 40, [[MA453]], Fall 2008, [[user:walther|Prof. Walther]]=
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==Problem Statement==
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''Could somebody please state the problem?''
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==Discussion==
 
It seems to me that |U(r)| x |U(s)| x gcd(r,s) = |U(rs)|.  All of the integers in Problem 38 had a gcd of 1, but 4 and 10 have a gcd of 2.  I thought of a couple other examples that this works for (2 and 4 is a simple example that holds).
 
It seems to me that |U(r)| x |U(s)| x gcd(r,s) = |U(rs)|.  All of the integers in Problem 38 had a gcd of 1, but 4 and 10 have a gcd of 2.  I thought of a couple other examples that this works for (2 and 4 is a simple example that holds).
  
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I thought that if Let U(r)=a U(s)=b if either one or both r or s is prime then |U(rs)|=2*(ab). Same thing you have but said differently
 
I thought that if Let U(r)=a U(s)=b if either one or both r or s is prime then |U(rs)|=2*(ab). Same thing you have but said differently
 
Jenny
 
Jenny
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[[HW3_MA453Fall2008walther|Back to HW3]]
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[[Main_Page_MA453Fall2008walther|Back to MA453 Fall 2008 Prof. Walther]]

Latest revision as of 16:06, 22 October 2010

HW3, Chapter 3, Problem 40, MA453, Fall 2008, Prof. Walther

Problem Statement

Could somebody please state the problem?


Discussion

It seems to me that |U(r)| x |U(s)| x gcd(r,s) = |U(rs)|. All of the integers in Problem 38 had a gcd of 1, but 4 and 10 have a gcd of 2. I thought of a couple other examples that this works for (2 and 4 is a simple example that holds).

-DK


I thought that if Let U(r)=a U(s)=b if either one or both r or s is prime then |U(rs)|=2*(ab). Same thing you have but said differently Jenny


Back to HW3

Back to MA453 Fall 2008 Prof. Walther

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