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Which can be stated more simply that if a probability is increased then the probability that your variable will be less than that probability will be the exact amount that you increased it by; but, only if the probability is always increasing and never decreases.
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I apologize this explanation may not be as helpful as you hoped, but it is very hard for me to explain without a picture or in person.
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Sincerely,
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Jared McNealis

Latest revision as of 04:42, 21 October 2008

I don't understand how the P[U<=F(x)] = F(x)can someone explain this?

//Comment

  This can be said because it was given to us that the function is a "non-decreasing function" and that U is a uniform random variable. This is enough information to make this step. So,
$ \begin{align} & {} \Pr(U \leq F(x)) = F(x)\quad \text{(because }\Pr(U \leq y) = y,\text{ since }U\text{ is uniform on the unit interval)} \end{align} $

Which can be stated more simply that if a probability is increased then the probability that your variable will be less than that probability will be the exact amount that you increased it by; but, only if the probability is always increasing and never decreases.

I apologize this explanation may not be as helpful as you hoped, but it is very hard for me to explain without a picture or in person.

Sincerely,

Jared McNealis

Alumni Liaison

Basic linear algebra uncovers and clarifies very important geometry and algebra.

Dr. Paul Garrett