(New page: ==Laplace Transform== The Laplace transform of a function ''f''(''t''), defined for all real numbers, is the function ''F''(''s''), defined by: :<math>F(s) = \mathcal{L} \left\{f(t)\righ...)
 
(Fourier transform)
 
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==Region of convergence==
 
==Region of convergence==
  
The Laplace transform ''F''(''s'') typically  exists for all complex numbers such that Re{''s''} > ''a'', where ''a'' is a real constant which depends on the growth behavior of ''f''(''t''), whereas the two-sided transform is defined in a range
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The Laplace transform ''F''(''s'') typically  exists for all complex numbers such that Re{''s''} > ''a'', where ''a'' is a real constant which depends on behavior of ''f''(''t''), whereas the transform is defined in a range ''a'' < Re{''s''} < ''b''.  The subset of values of ''s'' for which the Laplace transform exists is called the ''region of convergence'' (ROC) or the ''domain of convergence''.
  
''a'' < Re{''s''} < ''b''.  The subset of values of ''s'' for which the Laplace transform exists is called the ''region of convergence'' (ROC) or the ''domain of convergence''In the two-sided case, it is sometimes called the ''strip of convergence.''
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The integral defining the Laplace transform of a function may not exist when the function has infinite discontinuities in the interval of integration, or when it increases so rapidly that exp(-pt) cannot damp it sufficiently for convergence on the interval to take place and many other regions tooThere are no specific conditions that one can check a function against to know in all cases if its Laplace transform can be taken, other than to say the defining integral converges. It is however easy to give theorems on cases where it may or may not be taken.
  
The integral defining the Laplace transform of a function may fail to exist for various reasons. For example, when the function has infinite discontinuities in the interval of integration, or when it increases so rapidly that exp(-pt) cannot damp it sufficiently for convergence on the interval to take place. There are no specific conditions that one can check a function against to know in all cases if its Laplace transform can be taken,  other than to say the defining integral converges. It is however easy to give theorems on cases where it may or may not be taken.
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==Fourier transform==
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The continuous Fourier transform is equivalent to evaluating the bilateral Laplace transform with complex argument ''s'' = ''j''ω:
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<math>
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F(\omega) =  \mathcal{F}\left\{f(t)\right\}
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=  \mathcal{L}\left\{f(t)\right\}|_{s = j \omega}  =  F(s)|_{s = j \omega}
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=  \int_{-\infty}^{+\infty} e^{-\jmath \omega t} f(t)\,\mathrm{d}t.
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</math>
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Note that this expression excludes the scaling factor <math>\frac{1}{\sqrt{2 \pi}}</math>, which is often included in definitions of the Fourier transform.
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==Sources==
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Wikipedia
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signals and systems

Latest revision as of 20:24, 23 November 2008

Laplace Transform

The Laplace transform of a function f(t), defined for all real numbers, is the function F(s), defined by:

$ F(s) = \mathcal{L} \left\{f(t)\right\}=\int_{-\infty}^{\infty} e^{-st} f(t) \,dt. $

Region of convergence

The Laplace transform F(s) typically exists for all complex numbers such that Re{s} > a, where a is a real constant which depends on behavior of f(t), whereas the transform is defined in a range a < Re{s} < b. The subset of values of s for which the Laplace transform exists is called the region of convergence (ROC) or the domain of convergence.

The integral defining the Laplace transform of a function may not exist when the function has infinite discontinuities in the interval of integration, or when it increases so rapidly that exp(-pt) cannot damp it sufficiently for convergence on the interval to take place and many other regions too. There are no specific conditions that one can check a function against to know in all cases if its Laplace transform can be taken, other than to say the defining integral converges. It is however easy to give theorems on cases where it may or may not be taken.

Fourier transform

The continuous Fourier transform is equivalent to evaluating the bilateral Laplace transform with complex argument s = jω: $ F(\omega) = \mathcal{F}\left\{f(t)\right\} = \mathcal{L}\left\{f(t)\right\}|_{s = j \omega} = F(s)|_{s = j \omega} = \int_{-\infty}^{+\infty} e^{-\jmath \omega t} f(t)\,\mathrm{d}t. $

Note that this expression excludes the scaling factor $ \frac{1}{\sqrt{2 \pi}} $, which is often included in definitions of the Fourier transform.

Sources

Wikipedia

signals and systems

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