(New page: <math>e^{-at}u(t) ---> \frac{1}{a+j\omega} </math> where a is real and > 0)
 
 
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<math>e^{-at}u(t) ---> \frac{1}{a+j\omega} </math> where a is real and > 0
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<math>x(t)=e^{-at}u(t),\text{ where }a\text{ is real,}a>0 \longrightarrow {\mathcal X}(\omega)=\frac{1}{a+j\omega} </math>

Latest revision as of 11:10, 14 November 2008

$ x(t)=e^{-at}u(t),\text{ where }a\text{ is real,}a>0 \longrightarrow {\mathcal X}(\omega)=\frac{1}{a+j\omega} $

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Ryne Rayburn