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<math>h(t) = 7\delta(t-4) \!</math> | <math>h(t) = 7\delta(t-4) \!</math> | ||
− | <math>H(s) = 7e^{- | + | <math>H(s) = 7e^{-4s} \!</math> |
===HW 4.1 Response=== | ===HW 4.1 Response=== | ||
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+ | HW 4.1 signal | ||
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+ | <math>\frac{1}{2j}(e^{j4\pi t}-e^{-j4\pi t}) + \frac{1}{2}(e^{j3\pi t} + e^{-j3\pi t}) + e^{j2\pi t}</math> | ||
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+ | The response is equal to the convolution of the input signal and the system. | ||
+ | |||
+ | <math>7e^{-4jt}\frac{1}{2j}(e^{j4\pi t}-e^{-j4\pi t}) + 7e^{-4jt}\frac{1}{2}(e^{j3\pi t} +e^{-j3\pi t}) + 7e^{-4jt}e^{j2\pi t}</math> |
Latest revision as of 16:36, 26 September 2008
The CT LTI Signal
$ y(t) = 7x(t-4) \! $
The Unit Impulse Response
$ y(t) = 7x(t-4) \! $
$ h(t) = 7\delta(t-4) \! $
$ H(s) = 7e^{-4s} \! $
HW 4.1 Response
HW 4.1 signal
$ \frac{1}{2j}(e^{j4\pi t}-e^{-j4\pi t}) + \frac{1}{2}(e^{j3\pi t} + e^{-j3\pi t}) + e^{j2\pi t} $
The response is equal to the convolution of the input signal and the system.
$ 7e^{-4jt}\frac{1}{2j}(e^{j4\pi t}-e^{-j4\pi t}) + 7e^{-4jt}\frac{1}{2}(e^{j3\pi t} +e^{-j3\pi t}) + 7e^{-4jt}e^{j2\pi t} $