(HW 4.1 Response)
 
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<math>h(t) = 7\delta(t-4) \!</math>
 
<math>h(t) = 7\delta(t-4) \!</math>
  
<math>H(s) = 7e^{-4jw} \!</math>
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<math>H(s) = 7e^{-4s} \!</math>
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===HW 4.1 Response===
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HW 4.1 signal
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<math>\frac{1}{2j}(e^{j4\pi t}-e^{-j4\pi t}) + \frac{1}{2}(e^{j3\pi t} + e^{-j3\pi t}) + e^{j2\pi t}</math>
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The response is equal to the convolution of the input signal and the system.
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<math>7e^{-4jt}\frac{1}{2j}(e^{j4\pi t}-e^{-j4\pi t}) + 7e^{-4jt}\frac{1}{2}(e^{j3\pi t} +e^{-j3\pi t}) + 7e^{-4jt}e^{j2\pi t}</math>

Latest revision as of 16:36, 26 September 2008

The CT LTI Signal

$ y(t) = 7x(t-4) \! $

The Unit Impulse Response

$ y(t) = 7x(t-4) \! $

$ h(t) = 7\delta(t-4) \! $

$ H(s) = 7e^{-4s} \! $

HW 4.1 Response

HW 4.1 signal

$ \frac{1}{2j}(e^{j4\pi t}-e^{-j4\pi t}) + \frac{1}{2}(e^{j3\pi t} + e^{-j3\pi t}) + e^{j2\pi t} $

The response is equal to the convolution of the input signal and the system.

$ 7e^{-4jt}\frac{1}{2j}(e^{j4\pi t}-e^{-j4\pi t}) + 7e^{-4jt}\frac{1}{2}(e^{j3\pi t} +e^{-j3\pi t}) + 7e^{-4jt}e^{j2\pi t} $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood