(New page: ==Periodic CT Signal== <math>x(t) = 2sin(1000\pi t) + \frac{4\pi}{3} - cos(2000\pi t)\ </math> ==Fourier Series Coefficients==)
 
 
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[[Category:Fourier series]]
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[[Category:signals and systems]]
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== Example of Computation of Fourier series of a CT SIGNAL ==
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A [[Signals_and_systems_practice_problems_list|practice problem on "Signals and Systems"]]
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----
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==Periodic CT Signal==
 
==Periodic CT Signal==
<math>x(t) = 2sin(1000\pi t) + \frac{4\pi}{3} - cos(2000\pi t)\ </math>
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<math>x(t) = \frac{4\pi}{3} + \frac{1}{2}sin(1000\pi t) - cos(1000\pi t) \ </math>
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==Rewritten in <math>e^{jw_0}</math> Form==
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<math>x(t) =  \frac{4\pi}{3} + \frac{1}{j2000}(e^{j1000\pi t}+e^{j-1000\pi t}) - \frac{1}{j1000}(e^{j1000\pi t}-e^{j-1000\pi t})</math>
  
 
==Fourier Series Coefficients==
 
==Fourier Series Coefficients==
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<math>a_0 = \frac{4\pi}{3}</math>
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<math>a_1 = \frac{1}{1000}</math>
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<math>w_0 = 1000\pi\ </math>
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----
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[[Signals_and_systems_practice_problems_list|Back to Practice Problems on Signals and Systems]]

Latest revision as of 10:06, 16 September 2013


Example of Computation of Fourier series of a CT SIGNAL

A practice problem on "Signals and Systems"


Periodic CT Signal

$ x(t) = \frac{4\pi}{3} + \frac{1}{2}sin(1000\pi t) - cos(1000\pi t) \ $

Rewritten in $ e^{jw_0} $ Form

$ x(t) = \frac{4\pi}{3} + \frac{1}{j2000}(e^{j1000\pi t}+e^{j-1000\pi t}) - \frac{1}{j1000}(e^{j1000\pi t}-e^{j-1000\pi t}) $

Fourier Series Coefficients

$ a_0 = \frac{4\pi}{3} $

$ a_1 = \frac{1}{1000} $

$ w_0 = 1000\pi\ $


Back to Practice Problems on Signals and Systems

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