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== GUESS THE PERIODIC SIGNAL == | == GUESS THE PERIODIC SIGNAL == | ||
− | 1. <math>x(t)\!</math> is an <math>odd\!</math> function. | + | 1. The function <math>x(t)\!</math> is an <math>odd\!</math> function. |
<br> | <br> | ||
− | 2. <math>x(t)\!</math> has a fundamental period of <math>T = 9\!</math> | + | 2. x(t) is <math>real\!</math>. |
+ | <br> | ||
+ | |||
+ | 2. <math>x(t)\!</math> has a fundamental period of <math>T = 9\!</math>. | ||
<br> | <br> | ||
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− | 4. The function is offset by a value of +1 | + | 4. The function is offset by a value of +1. |
+ | <br> | ||
+ | |||
+ | 5. Finally, <math>a_{0} = 1\!</math>. | ||
<br> | <br> | ||
== ANSWER == | == ANSWER == | ||
− | <math>5cos(\frac{2\pi}{9}t)+1\!</math> | + | <math>x(t) = 5cos(\frac{2\pi}{9}t)+1\!</math> |
Latest revision as of 12:28, 25 September 2008
GUESS THE PERIODIC SIGNAL
1. The function $ x(t)\! $ is an $ odd\! $ function.
2. x(t) is $ real\! $.
2. $ x(t)\! $ has a fundamental period of $ T = 9\! $.
3. The Pk-Pk of the function is 10.
4. The function is offset by a value of +1.
5. Finally, $ a_{0} = 1\! $.
ANSWER
$ x(t) = 5cos(\frac{2\pi}{9}t)+1\! $