Difference between revisions of "HW4.5 Miles Whittaker ECE301Fall2008mboutin" - Rhea

Latest revision as of 15:46, 26 September 2008

Supposing we are given a signal $$ x(t) $$

1) $$ x(t) $$ is real and odd

2) $$ x(t) $$ is periodic with period $$ T = 5 $$

3) $a_{0}=0$

4) peak to peak value of 3

Specify a signal that satisfies the given conditions.

$signal=\frac{3}{2}sin(\frac{2\pi}{5}t)$

@@ Line 5: / Line 5: @@
 ) <math>x(t)</math> is real and odd
-) <math>x(t)</math> is periodic with period <math>T = 5</math> and has Fourier coefficients <math>a_{k}</math>
+) <math>x(t)</math> is periodic with period <math>T = 5</math>
+) <math>a_{0}=0</math>
+) peak to peak value of 3
-) <math>a_{k}=0</math> for <math>k<0</math> and <math>k>2</math>
-) <math>\frac{1}{2}\int_{0}^{4}|x(t)|^2dt=1</math>
 Specify a signal that satisfies the given conditions.
 == Answer ==
+<math>signal=\frac{3}{2}sin(\frac{2\pi}{5}t)</math>
 </font>