m (4.2a Emir Kavurmacioglu moved to 4.1a Emir Kavurmacioglu: Improperly named originally)
 
(No difference)

Latest revision as of 06:40, 15 October 2008

Start out by replacing the value of Y by N-X.

You then get

            P(N-X) = (N N-X) * [P^(N-X)] * [(1-P)^(N-(N-X))]
            P(N-X) = (N N-X) * [(1-P)^X] * [P^(N-X)

Then just expand the combination and prove that it is equal to (N X).

The last step is to define a new variable P' = 1-P, which is the probability parameter for Y.

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood