(New page: The input to the system is e^2jt which can be re-written as: cos(t)+2jsin(t). Its response to this signal is t*e^-2jt which can be rewritten as: t*cos(t)-2j*sin(...) |
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| − | The input to the system is e^2jt which can be re-written as: | + | The input to the system is <math>e^{2jt}</math> which can be re-written as: |
cos(t)+2jsin(t). | cos(t)+2jsin(t). | ||
| − | Its response to this signal is t*e^-2jt which can be rewritten as: | + | Its response to this signal is <math>t*e^{-2jt}</math> which can be rewritten as: |
t*cos(t)-2j*sin(t) | t*cos(t)-2j*sin(t) | ||
Since the system is linear, the input of cos(2t) should yeild a result of: | Since the system is linear, the input of cos(2t) should yeild a result of: | ||
t*cos(2t) | t*cos(2t) | ||
Latest revision as of 05:27, 17 September 2008
The input to the system is $ e^{2jt} $ which can be re-written as:
cos(t)+2jsin(t).
Its response to this signal is $ t*e^{-2jt} $ which can be rewritten as:
t*cos(t)-2j*sin(t)
Since the system is linear, the input of cos(2t) should yeild a result of:
t*cos(2t)
