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No the system is not time invariant because for every time shift (k + 1) in the input there is a change in the amplitude of the output by (k + 1)^2. | No the system is not time invariant because for every time shift (k + 1) in the input there is a change in the amplitude of the output by (k + 1)^2. | ||
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| + | '''6 b)''' | ||
| + | An input X[n] = u[n] should produce an output Y[n] = u[n-1] if we assume the system is linear. | ||
Latest revision as of 16:38, 12 September 2008
6 a) No the system is not time invariant because for every time shift (k + 1) in the input there is a change in the amplitude of the output by (k + 1)^2.
6 b) An input X[n] = u[n] should produce an output Y[n] = u[n-1] if we assume the system is linear.
