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The system is defiantly not time invariant. When the signal is shifted the output is shifted also but a different magnitude is applied to the output, showing that time affects the output.
 
The system is defiantly not time invariant. When the signal is shifted the output is shifted also but a different magnitude is applied to the output, showing that time affects the output.
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Sine we are talking about DT a setup of
 
Sine we are talking about DT a setup of
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<math>X[n]=\sum_{k=-\infty}^{\infty}</math> &delta;[n-k].
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However for <math>u[n]</math> we will need to cap off the <math>-\infty</math> to 0, since the for all values less then 0 the unit step would produce 0.
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X[n]=<math>\sum_{k=0}^{\infty}</math> &delta;[n-k].

Latest revision as of 14:34, 12 September 2008

The system is defiantly not time invariant. When the signal is shifted the output is shifted also but a different magnitude is applied to the output, showing that time affects the output.


Sine we are talking about DT a setup of

$ X[n]=\sum_{k=-\infty}^{\infty} $ δ[n-k].

However for $ u[n] $ we will need to cap off the $ -\infty $ to 0, since the for all values less then 0 the unit step would produce 0.

X[n]=$ \sum_{k=0}^{\infty} $ δ[n-k].

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Jeff McNeal