(→Part 2) |
(→Part 2) |
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| − | I haven't played around with matlab enough to know how to create the signal | + | I haven't played around with matlab enough to know how to create the signal needed with my own code, so I used the same code that Ben Laskowski used: |
---- | ---- | ||
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for count=1:period/delta:(nperiod+8)*period/delta | for count=1:period/delta:(nperiod+8)*period/delta | ||
| + | |||
y(1,count:size(y,2))=y(1,count:size(y,2))+f(1,1:size(y,2)-count+1); | y(1,count:size(y,2))=y(1,count:size(y,2))+f(1,1:size(y,2)-count+1); | ||
| + | |||
end | end | ||
Latest revision as of 14:14, 12 September 2008
Part 1
Choose the signal $ x(t)=cos(t) $ which is periodic.
File:Ctsignal.jpg
300px
Sampling ever interger yields
File:Dtsignal.jpg
300px
This is $ x[n]=cos(n) $
but sampling at a frequency of $ \pi/4 $ yields
File:Dtsignal1.jpg
300px
This is $ x[n]=cos(\pi/4n) $
Part 2
This is $ x(t)=e^{-t}cos(20t) $ as the nonperiodic signal.
File:Ctsignal3.jpg
300px
I haven't played around with matlab enough to know how to create the signal needed with my own code, so I used the same code that Ben Laskowski used:
"y=zeros(size(x));
for count=1:period/delta:(nperiod+8)*period/delta
y(1,count:size(y,2))=y(1,count:size(y,2))+f(1,1:size(y,2)-count+1);
end
plot(x,y)"
File:Ctsignal4.jpg
300px
