(Finding the bug)
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<pre>%    Ts was originally set to 1/13 (aka T0) and the graph displayed only one cycle. Since we want 13
 
<pre>%    Ts was originally set to 1/13 (aka T0) and the graph displayed only one cycle. Since we want 13
%    cycles, divide this previous Ts value by 13 again. Using Ts = T0/13 the proper grph is shown
+
%    cycles, divide this previous Ts value by 13 again. Using Ts = T0/13 the proper graph is shown.
  
 
F0 =13;  
 
F0 =13;  

Latest revision as of 09:46, 12 September 2008

Finding the bug

%    Ts was originally set to 1/13 (aka T0) and the graph displayed only one cycle. Since we want 13
%    cycles, divide this previous Ts value by 13 again. Using Ts = T0/13 the proper graph is shown.

F0 =13; 
T0 =1/F0; 
Ts = T0/13; 
t  = 0:Ts:13*T0; 
x = real(exp(j*(2*pi*F0*t-pi/2)));
plot(t,x)

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