(New page: == part a == it can't be a time invariant because output is not same. <math>X_k[n] = \delta[n-k]</math> <math>\delta[n-k]\rightarrow time delay\rightarrow\delta[n-k-n_0]\rightarrow sys...) |
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<math>\delta[n-k]\rightarrow time delay\rightarrow\delta[n-k-n_0]\rightarrow system \rightarrow (k+n_0+1)^2\delta[n-(k+n_0+1)]</math> | <math>\delta[n-k]\rightarrow time delay\rightarrow\delta[n-k-n_0]\rightarrow system \rightarrow (k+n_0+1)^2\delta[n-(k+n_0+1)]</math> | ||
| − | <math>\delta[n-k]\rightarrow system \rightarrow Y_k[n] \rightarrow</math> | + | <math>\delta[n-k]\rightarrow system \rightarrow Y_k[n] \rightarrow time delay \rightarrow (k+1)^2\delta[n-(k+n_0+1)] </math> |
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| + | |||
| + | == part b == | ||
| + | since it is linear | ||
| + | input would be X[n] = u[n] | ||
Latest revision as of 18:36, 11 September 2008
part a
it can't be a time invariant because output is not same.
$ X_k[n] = \delta[n-k] $
$ \delta[n-k]\rightarrow time delay\rightarrow\delta[n-k-n_0]\rightarrow system \rightarrow (k+n_0+1)^2\delta[n-(k+n_0+1)] $
$ \delta[n-k]\rightarrow system \rightarrow Y_k[n] \rightarrow time delay \rightarrow (k+1)^2\delta[n-(k+n_0+1)] $
part b
since it is linear input would be X[n] = u[n]
