(One intermediate revision by the same user not shown) | |||
Line 20: | Line 20: | ||
</pre> | </pre> | ||
− | The result is the desired graph: | + | The result is the desired graph of 13 cycles: |
+ | |||
+ | [[Image:13HzCorrect_ECE301Fall2008mboutin.JPG]] |
Latest revision as of 13:13, 11 September 2008
Problem with MATLAB Code
F0 =13; T0 =1/F0; Ts = 0.07; t = 0:Ts:13*T0; x = real(exp(j*(2*pi*F0*t-pi/2))); plot(t,x)
The problem with the above MATLAB code is that the time vector interval Ts = 0.07 sec is too small compared to the period of the signal which is 1/13 $ \approx $ 0.0769 sec. This bug can be fixed by letting Ts = 0.001 sec:
F0 =13; T0 =1/F0; Ts = 0.001; t = 0:Ts:13*T0; x = real(exp(j*(2*pi*F0*t-pi/2))); plot(t,x)
The result is the desired graph of 13 cycles: