(New page: == Time Invariant System == A time invariant system means that the output of the system doesn't depend on the time. In other words, there is an input <math>\,x(t)</math> with an output <m...)
 
(Example of Time Invariance)
 
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== Example of Time Invariance ==
 
== Example of Time Invariance ==
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Take <math>\,x(t) = e^t</math>. This is run through a time delay, which delays it by t0, then through a system which transforms it to <math>\,y(t) = 10x(t)</math>.
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::<math>\,x(t) = e^t ---> x(t-t0) = e^{(t-t0)} ---> y(t-t0) = 10e^{(t-t0)}</math>
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Now the signal is run through the system first, then the time delay.
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::<math>\,x(t) = e^t ---> y1(t) = 10e^t ---> y1(t-t0) = 10e^{(t-t0)}</math>
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<math>\,y(t-t0) = y1(t-t0)</math>.
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Thus, the system is time invariant.

Latest revision as of 05:44, 10 September 2008

Time Invariant System

A time invariant system means that the output of the system doesn't depend on the time. In other words, there is an input $ \,x(t) $ with an output $ \,y(t) $. If the input is shifted by time $ \,t0 $ so that $ \,x(t-t0) $ yields an output $ \,y(t-t0) $


Example of Time Invariance

Take $ \,x(t) = e^t $. This is run through a time delay, which delays it by t0, then through a system which transforms it to $ \,y(t) = 10x(t) $.

$ \,x(t) = e^t ---> x(t-t0) = e^{(t-t0)} ---> y(t-t0) = 10e^{(t-t0)} $

Now the signal is run through the system first, then the time delay.

$ \,x(t) = e^t ---> y1(t) = 10e^t ---> y1(t-t0) = 10e^{(t-t0)} $

$ \,y(t-t0) = y1(t-t0) $.


Thus, the system is time invariant.

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