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m (→Second Part) |
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Question: Assuming that this system is linear, what input X[n] would yield the output Y[n]=u[n-1]? | Question: Assuming that this system is linear, what input X[n] would yield the output Y[n]=u[n-1]? | ||
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| + | **on my to-do list. | ||
Revision as of 10:10, 10 September 2008
Homework 2 Ben Horst: A :: B :: C :: D :: E
Given the system
| Input | Output | |
| X0[n]=δ[n] | -> | Y0[n]=δ[n-1] |
| X1[n]=δ[n-1] | -> | Y1[n]=4δ[n-2] |
| X2[n]=δ[n-2] | -> | Y2[n]=9 δ[n-3] |
| X3[n]=δ[n-3] | -> | Y3[n]=16 δ[n-4] |
| ... | ... | |
| Xk[n]=δ[n-k] | -> | Yk[n]=(k+1)2 δ[n-(k+1)] |
For any non-negative integer k
Test for Time Invariance
Start with X2[n]=δ[n-2]
Delay the signal by 2 => X2[n] = δ[n-4]
Then run the signal through the system:
X2[n] = δ[n-4] -> system -> Y2 = 25δ[n-5]
Repeat in reverse...
Run the signal through the system:
X2[n]=δ[n-2] -> system -> Y2 = 9δ[n-3]
Then delay the signal by 2 => Y2 = 9δ[n-5]
Since 9δ[n-5] ≠ 25δ[n-5], the system is not Time Invariant.
Second Part
Question: Assuming that this system is linear, what input X[n] would yield the output Y[n]=u[n-1]?
- on my to-do list.
