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| − | minimum sampling frequency <math>\dfrac{1}{T} | + | minimum sampling frequency <math>\dfrac{1}{T}\ge\dfrac{2}{a}</math> <math>f\ge\dfrac{2}{a}</math> <math>T\le\dfrac{a}{2}</math><br> |
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https://www.projectrhea.org/rhea/dropbox_/381ea5db244c12bb92e6de3206725a7a/Wan82_CS5-4.PNG<br> | https://www.projectrhea.org/rhea/dropbox_/381ea5db244c12bb92e6de3206725a7a/Wan82_CS5-4.PNG<br> | ||
<br> | <br> | ||
| + | |||
---- | ---- | ||
| + | ===Similar Problem=== | ||
| + | [https://engineering.purdue.edu/ECE/Academics/Graduates/Archived_QE_August_13/CS-5.pdf?dl=1 2013 QE CS5 Prob1]<br> | ||
| + | [https://engineering.purdue.edu/ECE/Academics/Graduates/Archived_QE_August_09/CS-5%20QE%2009.pdf?dl=1 2009 QE CS5 Prob1]<br> | ||
| + | [https://engineering.purdue.edu/ECE/Academics/Graduates/Archived_QE_August_08/CS-5%20QE%2008.pdf?dl=1 2008 QE CS5 Prob3]<br> | ||
| + | |||
| + | ---- | ||
| + | |||
[[QE_2017_CS-5|Back to QE CS question 5, August 2017]] | [[QE_2017_CS-5|Back to QE CS question 5, August 2017]] | ||
[[ECE_PhD_Qualifying_Exams|Back to ECE Qualifying Exams (QE) page]] | [[ECE_PhD_Qualifying_Exams|Back to ECE Qualifying Exams (QE) page]] | ||
Latest revision as of 11:00, 25 February 2019
Communication Signal (CS)
Question 5: Image Processing
August 2017 Problem 2
Solution
a)
$ sinc^2(\dfrac{t}{a}) \Rightarrow |a|\Lambda(af) $ (CTFT)
b)
$ y(n)=sinc^2(\dfrac{nT}{a}) \Rightarrow X_s(f)=\dfrac{1}{T}\sum_{k=-\infty}^{\infty} X(f-kF)=\dfrac{|a|}{T}\sum_{k=-\infty}^{\infty}\Lambda(a(f-\dfrac{k}{T})) $
c)
minimum sampling frequency $ \dfrac{1}{T}\ge\dfrac{2}{a} $ $ f\ge\dfrac{2}{a} $ $ T\le\dfrac{a}{2} $
d)
$ T=\dfrac{a}{2} $
e)
$ T=a $
Similar Problem
2013 QE CS5 Prob1
2009 QE CS5 Prob1
2008 QE CS5 Prob3
