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[[Category:bonus point project]]
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= CTFT of periodic signals with properties =
  
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= CT Fourier Series for periodic signals and some properties with proofs=
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{| border="1" class="wikitable"
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|-
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! Function
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! CTFT
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|-
  
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===== - Fourier series of periodic signals =====
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|<math>sin(\omega_0t) </math>
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|<math>\frac{\pi}{j}(\delta(\omega - \omega_0) - \delta(\omega+\omega_0))</math>
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|-
  
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|<math>cos(\omega_0t) </math>
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|<math>\pi(\delta(\omega - \omega_0) + \delta(\omega+\omega_0))</math>
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|-
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|<math>e^{j\omega_0t} </math>
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|<math>2\pi\delta(\omega - \omega_0) </math>
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|-
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| <math>\sum^{\infty}_{k=-\infty} a_{k}e^{ikw_{0}t}</math>
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| <math>2\pi\sum^{\infty}_{k=-\infty}a_{k}\delta(w-kw_{0}) \ </math>
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|-
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| <math>\sum^{\infty}_{n=-\infty} \delta(t-nT)  \ </math>
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| <math>\frac{2\pi}{T}\sum^{\infty}_{k=-\infty}\delta(w-\frac{2\pi k}{T})</math>
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|-}
  
 
{| border="1" class="wikitable"
 
{| border="1" class="wikitable"
 
|-
 
|-
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! Function
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! Name
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! Fourier Series
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! <math> x(t) \longrightarrow \ </math>
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! <math> \mathcal{X}(\omega) </math>
 
! Proof
 
! Proof
 
|-
 
|-
  
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|<math>sin(\omega_0t) </math>
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| Linearity
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|<math>\frac{1}{2j}e^{j\omega_0 t} - \frac{1}{2j}e^{-j\omega_0 t} </math>
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| <math> ax(t) + by(t) \  </math>
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|
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| <math> a \mathcal{X}(\omega) + b \mathcal{Y} (\omega) </math>
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| <math>\mathfrak{F}(ax(t) + by(t)) = \int_{-\infty}^{\infty}[ax(t) + by(t)]e^{-j\omega t} dt</math><br />
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<math>\int_{-\infty}^{\infty}ax(t)e^{-j\omega t} dt + \int_{-\infty}^{\infty}by(t)e^{-j\omega t} dt</math><br />
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<math>=a\mathcal{X}(\omega) + b\mathcal{Y}(\omega) </math>
 
|-
 
|-
  
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|<math>cos(\omega_0t) </math>
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| Time Shifting
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|<math>\frac{1}{2}e^{j\omega_0 t} + \frac{1}{2}e^{-j\omega_0 t} </math>
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| <math> x(t-t_0) \  </math>
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|
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| <math>e^{-j\omega t_0}X(\omega)</math>
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| <math>\mathfrak{F}(x(t - t_{o})) = \int_{-\infty}^{\infty}x(t-t_{0})e^{-j\omega t} dt</math><br />
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let <math> t' = t - t_{o} </math><br />
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<math>\int_{-\infty}^{\infty}x(t')e^{-j\omega (t'+t_{o})} dt' </math><br />
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<math>= e^{-j\omega t_{o}}\int_{-\infty}^{\infty}x(t')e^{-j\omega t'} dt' </math><br />
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<math>= e^{-j\omega t_{o}}\mathcal{X}(\omega)</math> <br />
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|-
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| Frequency Shifting
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| <math>e^{j\omega_0 t}x(t)</math>
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| <math> \mathcal{X} (\omega - \omega_0) </math>
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| Refer to Time Shifting section
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|-
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| Conjugation
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| <math> x^{*}(t) \  </math>
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| <math> \mathcal{X}^{*} (-\omega)</math>
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| <math> \mathcal{X}^{*}(-\omega) = \int_{-\infty}^{\infty} (x(t)e^{j\omega t}dt)^{*} </math> <br />
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<math>= \int_{-\infty}^{\infty} x^{*}(t)e^{-j\omega t}dt </math> <br />
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<math>=\mathfrak{F}(x(t)^{*}) </math>
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|-
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| Scaling
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| <math> x(at) \  </math>
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| <math>\frac{1}{|a|} \mathcal{X} (\frac{\omega}{a})</math>
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| <math> \int_{-\infty}^{\infty} x(at)e^{-j\omega t}dt  </math> <br />
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let <math> t' = at </math><br />
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<math>= \int_{-\infty}^{\infty} x(t')e^{-j\omega \frac{t'}{a}}\frac{dt'}{a}, a > 0 </math> <br />
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<math>= -\int_{-\infty}^{\infty} x(t')e^{-j\omega \frac{t'}{a}}\frac{dt'}{a}, a < 0 </math> <br />
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<math>=\frac{1}{|a|} \mathcal{X} (\frac{\omega}{a})</math>
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|-
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| Convolution
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| <math>x(t)*y(t) \ </math>
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| <math> \mathcal{X}(\omega)\mathcal{Y}(\omega) \!</math>
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| Remember that <math> x(t)*y(t) =\int_{-\infty}^{\infty} x(t')y(t-t')dt' </math><br />
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<math>\mathfrak{F}(x(t)*y(t)) = \int_{-\infty}^{\infty}[\int_{-\infty}^{\infty} x(t')y(t-t')dt' ]e^{-j\omega t}dt </math><br />
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Replace <math>e^{-j\omega t}</math> by <math> e^{-j\omega( t - t' )} e^{-j\omega t' }</math><br />
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<math>= \int_{-\infty}^{\infty}[\int_{-\infty}^{\infty} x(t')y(t-t')dt' ]e^{-j\omega( t - t' )} e^{-j\omega t' }dt </math><br />
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<math>= \int_{-\infty}^{\infty}e^{-j\omega t' }dt'[\int_{-\infty}^{\infty} x(t')y(t-t')e^{-j\omega( t - t' )}dt'] </math><br />
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<math>= \chi(\omega)\gamma(\omega)</math><br />
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|-
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| Multiplication
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| <math>x(t)y(t) \ </math>  
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| <math>\frac{1}{2\pi} \mathcal{X}(\omega)*\mathcal{Y}(\omega) </math>
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| Refer to Convolution section
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|-
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| Differentiation
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| <math> \frac{d}{dt} x(t) \  </math>
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| <math>j\omega \mathcal{X} (\omega)</math>
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| <math> x(t) = \frac{1}{2\pi} \int_{-\infty}^{\infty}  \mathcal{X}(\omega)e^{j\omega t}d\omega</math> <br />
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<math>  \frac{d}{dt} x(t)= \frac{1}{2\pi} \int_{-\infty}^{\infty}  \mathcal{X}(\omega) [\frac{d}{dt}e^{j\omega t}] d\omega</math> <br />
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<math> \frac{d}{dt} x(t)= \frac{1}{2\pi} \int_{-\infty}^{\infty}  \mathcal{X}(\omega) j\omega e^{j\omega t} d\omega</math> <br />  
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|-
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| Duality
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| <math> \mathcal{X} (-t) </math>
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| <math> 2 \pi x (\omega) \  </math>
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| <math> 2\pi  \mathcal{X} (-\omega) = \int_{-\infty}^{\infty}  \mathcal{X}(t')e^{-j\omega t'}dt'</math> <br />
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let t = t' <br />
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<math>  = \int_{-\infty}^{\infty}  \mathcal{X}(t)e^{-j\omega t}dt</math> <br />
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= CTFT[x(t)] <br />
 
|-
 
|-
  
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|<math>e^{\alpha t}u(t) </math>
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| Parseval's Relation
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|<math>\frac{1}{\alpha + j\omega} </math>
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| | <math>\int_{-\infty}^{\infty} |x(t)|^2 dt = </math>
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|
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| <math> \frac{1}{2\pi} \int_{-\infty}^{\infty} |\mathcal{X}(w)|^2 dw</math>
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| <math> \int_{-\infty}^{\infty} x(t)x(t) dt =  \int_{-\infty}^{\infty}x(t)dt(\frac{1}{2\pi} \int_{-\infty}^{\infty}\mathcal{X}(\omega)e^{j\omega t}d\omega)</math><br />
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<math>= \frac{1}{2\pi}\int_{-\infty}^{\infty}\mathcal{X}(\omega)d\omega [\int_{-\infty}^{\infty}x(t)\frac{1}{2\pi}e^{j\omega t}]dt</math><br />
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<math>= \frac{1}{2\pi}\int_{-\infty}^{\infty}\chi(\omega)[\chi(-\omega)]d\omega</math><br />
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<math>= \frac{1}{2\pi }\int_{-\infty}^{\infty} | \mathcal{X} (\omega) |^{2}d\omega</math><br />
 
|-
 
|-
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}
 

Latest revision as of 23:52, 14 November 2018

CTFT of periodic signals with properties

Function CTFT
$ sin(\omega_0t) $ $ \frac{\pi}{j}(\delta(\omega - \omega_0) - \delta(\omega+\omega_0)) $
$ cos(\omega_0t) $ $ \pi(\delta(\omega - \omega_0) + \delta(\omega+\omega_0)) $
$ e^{j\omega_0t} $ $ 2\pi\delta(\omega - \omega_0) $
$ \sum^{\infty}_{k=-\infty} a_{k}e^{ikw_{0}t} $ $ 2\pi\sum^{\infty}_{k=-\infty}a_{k}\delta(w-kw_{0}) \ $
$ \sum^{\infty}_{n=-\infty} \delta(t-nT) \ $ $ \frac{2\pi}{T}\sum^{\infty}_{k=-\infty}\delta(w-\frac{2\pi k}{T}) $
Name $ x(t) \longrightarrow \ $ $ \mathcal{X}(\omega) $ Proof
Linearity $ ax(t) + by(t) \ $ $ a \mathcal{X}(\omega) + b \mathcal{Y} (\omega) $ $ \mathfrak{F}(ax(t) + by(t)) = \int_{-\infty}^{\infty}[ax(t) + by(t)]e^{-j\omega t} dt $

$ \int_{-\infty}^{\infty}ax(t)e^{-j\omega t} dt + \int_{-\infty}^{\infty}by(t)e^{-j\omega t} dt $
$ =a\mathcal{X}(\omega) + b\mathcal{Y}(\omega) $

Time Shifting $ x(t-t_0) \ $ $ e^{-j\omega t_0}X(\omega) $ $ \mathfrak{F}(x(t - t_{o})) = \int_{-\infty}^{\infty}x(t-t_{0})e^{-j\omega t} dt $

let $ t' = t - t_{o} $
$ \int_{-\infty}^{\infty}x(t')e^{-j\omega (t'+t_{o})} dt' $
$ = e^{-j\omega t_{o}}\int_{-\infty}^{\infty}x(t')e^{-j\omega t'} dt' $
$ = e^{-j\omega t_{o}}\mathcal{X}(\omega) $

Frequency Shifting $ e^{j\omega_0 t}x(t) $ $ \mathcal{X} (\omega - \omega_0) $ Refer to Time Shifting section
Conjugation $ x^{*}(t) \ $ $ \mathcal{X}^{*} (-\omega) $ $ \mathcal{X}^{*}(-\omega) = \int_{-\infty}^{\infty} (x(t)e^{j\omega t}dt)^{*} $

$ = \int_{-\infty}^{\infty} x^{*}(t)e^{-j\omega t}dt $
$ =\mathfrak{F}(x(t)^{*}) $

Scaling $ x(at) \ $ $ \frac{1}{|a|} \mathcal{X} (\frac{\omega}{a}) $ $ \int_{-\infty}^{\infty} x(at)e^{-j\omega t}dt $

let $ t' = at $
$ = \int_{-\infty}^{\infty} x(t')e^{-j\omega \frac{t'}{a}}\frac{dt'}{a}, a > 0 $
$ = -\int_{-\infty}^{\infty} x(t')e^{-j\omega \frac{t'}{a}}\frac{dt'}{a}, a < 0 $
$ =\frac{1}{|a|} \mathcal{X} (\frac{\omega}{a}) $

Convolution $ x(t)*y(t) \ $ $ \mathcal{X}(\omega)\mathcal{Y}(\omega) \! $ Remember that $ x(t)*y(t) =\int_{-\infty}^{\infty} x(t')y(t-t')dt' $

$ \mathfrak{F}(x(t)*y(t)) = \int_{-\infty}^{\infty}[\int_{-\infty}^{\infty} x(t')y(t-t')dt' ]e^{-j\omega t}dt $
Replace $ e^{-j\omega t} $ by $ e^{-j\omega( t - t' )} e^{-j\omega t' } $
$ = \int_{-\infty}^{\infty}[\int_{-\infty}^{\infty} x(t')y(t-t')dt' ]e^{-j\omega( t - t' )} e^{-j\omega t' }dt $
$ = \int_{-\infty}^{\infty}e^{-j\omega t' }dt'[\int_{-\infty}^{\infty} x(t')y(t-t')e^{-j\omega( t - t' )}dt'] $
$ = \chi(\omega)\gamma(\omega) $

Multiplication $ x(t)y(t) \ $ $ \frac{1}{2\pi} \mathcal{X}(\omega)*\mathcal{Y}(\omega) $ Refer to Convolution section
Differentiation $ \frac{d}{dt} x(t) \ $ $ j\omega \mathcal{X} (\omega) $ $ x(t) = \frac{1}{2\pi} \int_{-\infty}^{\infty} \mathcal{X}(\omega)e^{j\omega t}d\omega $

$ \frac{d}{dt} x(t)= \frac{1}{2\pi} \int_{-\infty}^{\infty} \mathcal{X}(\omega) [\frac{d}{dt}e^{j\omega t}] d\omega $
$ \frac{d}{dt} x(t)= \frac{1}{2\pi} \int_{-\infty}^{\infty} \mathcal{X}(\omega) j\omega e^{j\omega t} d\omega $

Duality $ \mathcal{X} (-t) $ $ 2 \pi x (\omega) \ $ $ 2\pi \mathcal{X} (-\omega) = \int_{-\infty}^{\infty} \mathcal{X}(t')e^{-j\omega t'}dt' $

let t = t'
$ = \int_{-\infty}^{\infty} \mathcal{X}(t)e^{-j\omega t}dt $
= CTFT[x(t)]

Parseval's Relation $ \int_{-\infty}^{\infty} |x(t)|^2 dt = $ $ \frac{1}{2\pi} \int_{-\infty}^{\infty} |\mathcal{X}(w)|^2 dw $ $ \int_{-\infty}^{\infty} x(t)x(t) dt = \int_{-\infty}^{\infty}x(t)dt(\frac{1}{2\pi} \int_{-\infty}^{\infty}\mathcal{X}(\omega)e^{j\omega t}d\omega) $

$ = \frac{1}{2\pi}\int_{-\infty}^{\infty}\mathcal{X}(\omega)d\omega [\int_{-\infty}^{\infty}x(t)\frac{1}{2\pi}e^{j\omega t}]dt $
$ = \frac{1}{2\pi}\int_{-\infty}^{\infty}\chi(\omega)[\chi(-\omega)]d\omega $
$ = \frac{1}{2\pi }\int_{-\infty}^{\infty} | \mathcal{X} (\omega) |^{2}d\omega $

Retrieved from "https://www.projectrhea.org/rhea/index.php?title=CTFT_periodic_signals_ECE301F18&oldid=75188"
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BSEE 2004, current Ph.D. student researching signal and image processing.

Landis Huffman