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<math>x[n]=</math><math>j^{n}</math> is a discrete time (DT) periodic signal. It's period is 4*k, where k is an integer. However, it's fundamental period is 4. | <math>x[n]=</math><math>j^{n}</math> is a discrete time (DT) periodic signal. It's period is 4*k, where k is an integer. However, it's fundamental period is 4. | ||
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<math>j^{1}=-1</math> | <math>j^{1}=-1</math> |
Revision as of 13:02, 4 September 2008
Periodic Function
$ x[n]= $$ j^{n} $ is a discrete time (DT) periodic signal. It's period is 4*k, where k is an integer. However, it's fundamental period is 4.
$ j^{1}=-1 $
$ j^{2}=-j $
$ j^{3}=1 $
$ j^{4}=j $
$ j^{5}=-1 $
$ j^{6}=-j $
$ j^{7}=1 $
$ j^{8}=j $