(Review by MRH added)
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*Review by Michael Hayashi
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*Review by Student 1
 
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**Author answer here
The examples you chose illustrated the Fourier transform well. A right arrow would help with the CTFT pair (in <math>\omega</math>) in the first example, and the example seems to flow the wrong direction: <br><math>X(f) = \mathcal{X}(\frac{\omega}{2\pi})</math><br>would more clearly establish that we want to obtain answers in terms of frequcny in Hertz. Ending the second example with a statement about the bidirectional nature of Fourier transform pairs would give even greater power to your examples.
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Revision as of 01:26, 15 October 2014


Questions and Comments for Fourier transform as a function of frequency $ \omega $ versus Fourier transform as a function of frequency f

A slecture by ECE student Dauren



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Basic linear algebra uncovers and clarifies very important geometry and algebra.

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