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Revision as of 18:42, 9 September 2008
Contents
Phasors
$ x(t)=Ae^{j\theta+\phi} $
Where A is the radius of the phasor and $ \phi $ if the offset.
Useful Phasors Facts
$ e^{j\theta} = \cos{\theta}+j\sin{\theta} $
$ Ae^{j[\theta+\phi]}=Ae^{j\theta}e^{j\phi} $
$ \cos{\theta}=\frac{e^{j\theta}+e^{-j\theta}}{2} $
$ \sin{\theta}=\frac{e^{j\theta}-e^{-j\theta}}{2j} $
$ |e^{j\theta}|=1 $
Energy
Discrete
$ Insert formula here $