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This slecture was reviewed by Khalid Tahboub:
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Comments for: '''[[The_principles_for_how_to_generate_random_samples_from_a_Gaussian_distribution|The principles for how to generate random samples from a Gaussian distribution]]'''
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A [https://www.projectrhea.org/learning/slectures.php slecture] by Joonsoo Kim
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Please leave me comment below if you have any questions, if you notice any errors or if you would like to discuss a topic further.
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'''Review by Khalid Tahboub:'''
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Great job! few minor remarks:
  
 
1) I think the first equation should be
 
1) I think the first equation should be
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4) I think it might give a nice demonstration if you plot the histogram of U and X to show that this method really functions in the desired way.
 
4) I think it might give a nice demonstration if you plot the histogram of U and X to show that this method really functions in the desired way.
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'''Write Question/Comment Here'''
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'''Write Question/Comment Here'''
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Back to [[The_principles_for_how_to_generate_random_samples_from_a_Gaussian_distribution|The principles for how to generate random samples from a Gaussian distribution]]

Latest revision as of 15:26, 14 May 2014

Comments for: The principles for how to generate random samples from a Gaussian distribution

A slecture by Joonsoo Kim



Please leave me comment below if you have any questions, if you notice any errors or if you would like to discuss a topic further.



Review by Khalid Tahboub:

Great job! few minor remarks:

1) I think the first equation should be

$ F^{-1}(u)=inf\{ x|F(x)\geq u, \quad u\in [0, 1] \} $

instead of

$ F^{-1}(u)=inf\{ x|F(x)\leq u, \quad u\in [0, 1] \} $
2) How we reach
$ X <- F^{-1}(U)\quad $
from
$ F^{-1}(u)=inf\{ x|F(x)\geq u, \quad u\in [0, 1] \} $
is not very clear to me


3)I think the equation

$ F(x) = \int_{-\infty}^x \lambda exp(-\lambda x') dx' = \int_0^x \lambda exp(-\lambda x') dx' = [-exp(-\lambda x')]_0^x = 1-exp(-\lambda x) \leq u $

should be instead

$ F(x) = \int_{-\infty}^x \lambda exp(-\lambda x') dx' = \int_0^x \lambda exp(-\lambda x') dx' = [-exp(-\lambda x')]_0^x = 1-exp(-\lambda x) \geq u $

4) I think it might give a nice demonstration if you plot the histogram of U and X to show that this method really functions in the desired way.


Write Question/Comment Here


Write Question/Comment Here



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