(→Finding the Inverse of Complex Numbers) |
(→Finding the Inverse of Complex Numbers) |
||
Line 1: | Line 1: | ||
− | |||
== Finding the Inverse of Complex Numbers == | == Finding the Inverse of Complex Numbers == | ||
− | <math>1 | + | <math>{(a+bi)^{-1}}={1\over(a + bi)} = {a\over a^2+b^2}+ \left( {-b\over a^2+b^2}\right)i</math> |
Revision as of 04:27, 2 September 2008
Finding the Inverse of Complex Numbers
$ {(a+bi)^{-1}}={1\over(a + bi)} = {a\over a^2+b^2}+ \left( {-b\over a^2+b^2}\right)i $