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[[Category:ECE440Fall2013Love]] [[Category:ECE440]] [[Category:ECE]] [[Category:Lab]] [[Category:communication systems]]
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[[Category:ECE440]] [[Category:ECE]] [[Category:Lab]] [[Category:communication systems]]
 
[[Category:discussion]]
 
[[Category:discussion]]
  
=Discussion page for [[ECE440F13LoveLab1|Lab 1 ECE440 Fall 2013]]=
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[[ECE 440|ECE 440]] > [[ECE440_Lab1|Lab 1]] > [[ECE440_Lab1_discussion|Discussion page]]
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=Discussion page for Lab 1=
  
 
This discussion board is used to clarify issues on the lab and pre-lab.
 
This discussion board is used to clarify issues on the lab and pre-lab.
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A: One can show that the RMS voltage of each spectral component is equal to the corresponding coefficient of the complex Fourier series. To show this, plug in the spectral component
 
A: One can show that the RMS voltage of each spectral component is equal to the corresponding coefficient of the complex Fourier series. To show this, plug in the spectral component
  
<math> a_k exp(j k w_0 t) <\math>
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<math> x_k (t) = a_k e^{j k w_0 t} </math>
  
 
from the complex Fourier series into the formula for RMS
 
from the complex Fourier series into the formula for RMS
  
<math> x_{RMS} = \sqrt{ \frac{1}{T} \int_T | x (t)|^2 dt  } </math>
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<math> x_{k,RMS} = \sqrt{ \frac{1}{T} \int_T | x_k (t)|^2 dt  } </math>.
  
  
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A: To combine the RMS voltages to get the net RMS of the first nine spectral components, use the following:
 
A: To combine the RMS voltages to get the net RMS of the first nine spectral components, use the following:
  
<math>V_{rms,net} = \sqrt{ v_0^2 + v_1^2 + ... + v_9^2}</math>
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<math>V_{rms,net} = \sqrt{ v_0^2 + v_1^2 + ... }</math>,
  
 
where v_i is the RMS of the i-th spectral component. By Parseval's theorem, Vrms,net should converge to the RMS voltage of the overall signal as the number of spectral components included in the sum approaches infinity.
 
where v_i is the RMS of the i-th spectral component. By Parseval's theorem, Vrms,net should converge to the RMS voltage of the overall signal as the number of spectral components included in the sum approaches infinity.
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A: A reference resistance is a resistance used in an instrument (e.g., Wavetek RMS Voltmeter) to measure the power of a signal. The power, P in watts, and voltage, V in volts, of the signal are related according to
 
A: A reference resistance is a resistance used in an instrument (e.g., Wavetek RMS Voltmeter) to measure the power of a signal. The power, P in watts, and voltage, V in volts, of the signal are related according to
  
<math>P=\frac{V^2}{R_{ref}}</math>,
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<math>P_{avg}=\frac{V_{rms}^2}{R_{ref}}</math>,
  
 
where <math>R_{ref}</math> is the reference resistance in ohms. Now, from the above relationship we can get the dBV of a signal from a dBm reading. Dividing each side by <math>10^{-3} W</math> and taking the <math>10\log </math> of each side, we get:
 
where <math>R_{ref}</math> is the reference resistance in ohms. Now, from the above relationship we can get the dBV of a signal from a dBm reading. Dividing each side by <math>10^{-3} W</math> and taking the <math>10\log </math> of each side, we get:
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[[ECE440F13LoveLab1|Back to Lab 1 ECE440 Fall 2013]]
 

Latest revision as of 09:08, 15 January 2014

ECE 440 > Lab 1 > Discussion page


Discussion page for Lab 1

This discussion board is used to clarify issues on the lab and pre-lab.


Q: How do I get the RMS voltage of spectral components on the 5th question?

A: One can show that the RMS voltage of each spectral component is equal to the corresponding coefficient of the complex Fourier series. To show this, plug in the spectral component

$ x_k (t) = a_k e^{j k w_0 t} $

from the complex Fourier series into the formula for RMS

$ x_{k,RMS} = \sqrt{ \frac{1}{T} \int_T | x_k (t)|^2 dt } $.



Q: Do the RMS voltage of the spectral components need to sum up to the total RMS voltage?

A: To combine the RMS voltages to get the net RMS of the first nine spectral components, use the following:

$ V_{rms,net} = \sqrt{ v_0^2 + v_1^2 + ... } $,

where v_i is the RMS of the i-th spectral component. By Parseval's theorem, Vrms,net should converge to the RMS voltage of the overall signal as the number of spectral components included in the sum approaches infinity.


Q: What is reference resistance? How to get the dBV of a signal from a dBm reading?

A: A reference resistance is a resistance used in an instrument (e.g., Wavetek RMS Voltmeter) to measure the power of a signal. The power, P in watts, and voltage, V in volts, of the signal are related according to

$ P_{avg}=\frac{V_{rms}^2}{R_{ref}} $,

where $ R_{ref} $ is the reference resistance in ohms. Now, from the above relationship we can get the dBV of a signal from a dBm reading. Dividing each side by $ 10^{-3} W $ and taking the $ 10\log $ of each side, we get:

$ 10\log\left(\frac{P}{10^{-3}W}\right)=10\log\left(\left(\frac{V}{\sqrt(R_{ref}\times 10^{-3}W)}\right)^2\right)=20\log\left(\frac{V}{\sqrt(R_{ref}\times 10^{-3} W})\right) $

Any $ R_{ref} $ can do, however, it is easiest if we pick $ R_{ref}=1000 \Omega $ in which case we get:

$ \text{Power reading in dBm}=\text{Voltage of signal in dBV} $.


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