(Computing the Inverse Fourier Transform)
 
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[[Category:problem solving]]
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[[Category:ECE301]]
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[[Category:ECE]]
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[[Category:Fourier transform]]
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[[Category:inverse Fourier transform]]
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[[Category:signals and systems]]
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== Example of Computation of inverse Fourier transform (CT signals) ==
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A [[CT_Fourier_transform_practice_problems_list|practice problem on CT Fourier transform]]
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==Computing the Inverse Fourier Transform==
 
==Computing the Inverse Fourier Transform==
  
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The inverse Fourier transform is defined as:
 
The inverse Fourier transform is defined as:
  
<math> x(t) = \int_{-infty}^{infty} \frac{X(w)}{2 \pi} e^{jwt} dw </math>
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<math> x(t) = \int_{-\infty}^{\infty} \frac{X(w)}{2 \pi} e^{jwt} dw </math>
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Using this formula to determine the signal:
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<math>\ x(t) = \frac{8 \pi}{2 \pi} \int_{-\infty}^{\infty} w e^{jwt} \delta(w-9) dw + \frac{2}{2 \pi} \int_{-\infty}^{\infty}w^{3} \delta(w-4 \pi) e^{jwt} dw </math>
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Now using the sifting property of the delta function we find that the signal is
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<math>\ x(t) = 36 e^{j9t} + 64 \pi^{2} e^{j4\pi t} </math>
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[[CT_Fourier_transform_practice_problems_list|Back to Practice Problems on CT Fourier transform]]

Latest revision as of 11:40, 16 September 2013

Example of Computation of inverse Fourier transform (CT signals)

A practice problem on CT Fourier transform


Computing the Inverse Fourier Transform

$ \ X(\omega)= 8 \pi w \delta(w-9) + 2 \pi w^{3} \delta(w-4 \pi) $

The inverse Fourier transform is defined as:

$ x(t) = \int_{-\infty}^{\infty} \frac{X(w)}{2 \pi} e^{jwt} dw $

Using this formula to determine the signal:

$ \ x(t) = \frac{8 \pi}{2 \pi} \int_{-\infty}^{\infty} w e^{jwt} \delta(w-9) dw + \frac{2}{2 \pi} \int_{-\infty}^{\infty}w^{3} \delta(w-4 \pi) e^{jwt} dw $

Now using the sifting property of the delta function we find that the signal is

$ \ x(t) = 36 e^{j9t} + 64 \pi^{2} e^{j4\pi t} $


Back to Practice Problems on CT Fourier transform

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Ryne Rayburn